1 75 11.34 5.67 .743

2 83 12.68 6.34 .658

Table 2 – Direct Measurement

Trial M&M Thickness (CM)

1 .642

2 .741

3 .683

Table 3 - Calculated Averages Method Calculated Average Thickness (cm)

Indirect (from Table 1) .700

Direct (from Table 2) .689

1. When you performed Step 2 of the procedure, you actually made a cylinder of M&Ms. The cylinder was rather "smushed," and the height of the cylinder was the thickness of an M&M. Recall that the equation for the volume of a cylinder is V = (3.14)r2h.

A. Rearrange the equation for "h." Show your work.

V = (3.14) r2h

V = (3.14) = 3.14r2h

(3.14)r2 3.14r2 V/(3.14)r2=h

B. Using the data from Table 1 and your equation, calculate the average thickness (height) of an M&M for each trial. Record your calculated values in Table 1. Hint: Students often forget that they must use the radius, and not the diameter, in the equation. Copy Table 1 into the assignment.

C. Trial 1: h = 75 / (3.14 x 5.67)2 h = 75 / (3.14 x 32.1489) h = 75 / 100.947546 h = 0.743 cm

Trial 2 h = 83 / (3.14 x 6.34)2 h = 83 / (3.14 x 40.1956) h = 83 / 126.214184 h = 0.658 cm

C. You now have two values for the thickness of an M&M in Table 1. Determine the average M&M thickness using these values and record your value in Table 3.

(0.743 + 0.658) / 2

= 1.401 / 2

= .700 cm

D. You have just determined a value for the thickness of an M&M using the indirect method. What makes this method