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Trial Volume (CM3) Diameter (CM) Radius (CM) M&M Thickness (CM)
1 75 11.34 5.67 .743
2 83 12.68 6.34 .658

Table 2 – Direct Measurement
Trial M&M Thickness (CM)
1 .642
2 .741
3 .683

Table 3 - Calculated Averages Method Calculated Average Thickness (cm)
Indirect (from Table 1) .700
Direct (from Table 2) .689

1. When you performed Step 2 of the procedure, you actually made a cylinder of M&Ms. The cylinder was rather "smushed," and the height of the cylinder was the thickness of an M&M. Recall that the equation for the volume of a cylinder is V = (3.14)r2h.
A. Rearrange the equation for "h." Show your work.
V = (3.14) r2h
V = (3.14) = 3.14r2h
(3.14)r2 3.14r2 V/(3.14)r2=h

B. Using the data from Table 1 and your equation, calculate the average thickness (height) of an M&M for each trial. Record your calculated values in Table 1. Hint: Students often forget that they must use the radius, and not the diameter, in the equation. Copy Table 1 into the assignment.
C. Trial 1: h = 75 / (3.14 x 5.67)2 h = 75 / (3.14 x 32.1489) h = 75 / 100.947546 h = 0.743 cm
Trial 2 h = 83 / (3.14 x 6.34)2 h = 83 / (3.14 x 40.1956) h = 83 / 126.214184 h = 0.658 cm
C. You now have two values for the thickness of an M&M in Table 1. Determine the average M&M thickness using these values and record your value in Table 3.
(0.743 + 0.658) / 2
= 1.401 / 2
= .700 cm
D. You have just determined a value for the thickness of an M&M using the indirect method. What makes this method

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