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Emily Shiang
6/27/13

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One box down, four to go. Easy, right? That’s what I thought as I filled in the ‘three’ box, again with a zero for the same reasons that I’d put a zero in the ‘four’ box. Four wouldn’t work because that would require three to be in four boxes, and then that wouldn’t leave room for any other numbers. Again, this was the reason that three, two, and one didn’t work. For three, too, the only possibility was zero.…

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This problem of the week has a main gain goal set upon boxes. There are five boxes numbered one through zero. Underneath the boxes have the numbers written under them. In the boxes, there are numbers that should be entered in the boxes that all evenly works out. For instance, the number that you put in box zero must be the same as the number of zeros that were used. The same procedures apply when using other boxes. The same number cannot be used in the box, for example, a four cannot be placed in box four or the number two cannot be enlisted in box two. The same number is tolerable to be used more than once. The only exception is that no number higher than four can be expended. My goal for this POW is to corroborate and demonstrate that I have found all solutions and that all solutions work and is credible.…

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There’s a standard 8 x 8 checkerboard made up by 64 small squares. Each square is able to combine with others squares to make other squares of different sizes. Our job is to find out how many squares there’s in total. Once you get all the number of squares get all the number of squares and feel confident with your answer you next explain how to find the number of squares on any size checkerboard. You will know you have the answer when no matter how what size board you have you can give a clear description of to easily compute the total number of squares. So basically what you’re doing is finding the total number of squares in a 8 x 8 checkerboard and pretty much finding an equation on how to find the total number of squares on any size board.…

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