# Pow 15

6 6 18 6 18 18 18 18 18 72 18 18 18 126 72 18 18 180 126 72 18 396 180 126 72 836 438 258 132

6 6 6 18 18 18 54 6 18 18 36 6 18 18 6 6

I then found the pattern that emerged in the upper data table interesting. So I decided to look into it further. At first I looked at the graph of the sum after birth to see what kind of relationship it was.

Sum vs Day

2000 1800 1600 1400 1200 1000 800 600 400 200 0 0

50

100

150

200 Series 1

250

300

350

400

As clearly shown the growth is exponential. I then tried to get a model for this data but could not get anything that fit it perfectly, which is what I was aiming for. So I moved on to looking for relationships in the data. I looked at the ratios and differences between the days and the sums, and rats born. But was unable to come up with anything. I then tried to look at other relationships between sterile rats, reproducible rats, and the sum before and after birth. Sum after birth # rats reproducable sum before birth # sterile 2 8 2 2 0 14 2 8 6 20 2 14 12 44 8 20 12 86 14 44 30 146 20 86 66 278 44 146 102 536 86 278 192 974 146 536 390 1808 278 974 696

Solution My solution for this problem was 1808 rats at the end of 1 year. I believe that this solution is correct because of the pattern noticed when looking at the compiled data table. Also because after creating the table shown above (last page) it was logical that that was how it worked out. Through the course of working on the problem I looked at various ways of solving and trying to find patterns and became familiar enough with the growth of the rats that my answer appears to be completely logical with no questions or discrepancies left open. Generalizations In order to generalize this problem I first looked into jumping straight to an explicit formula but quickly found that doing so would be highly improbable. So I then looked into a recursive function that would model the population. Looking at the growth logically I noticed that the first 3 dates 6 rats were due. Then on the 4th date (120) the number of rats born were going to be 6+ the number born 120 days earlier, or 3 dates back. Then if you continue this a recursive function emerges; such that:

2

U0 = 6 U1 = 6 U2 = 6 U n = (3(U n − 3 ) + 3(U n − 4 ) + 3(U n − 5 ) + ... + 3(U n − n ) )+ 6

What the...

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