Physics Lab Report
MAPUA INSTITUTE OF TECHNOLOGY
DEPARTMENT OF PHYSICS
EXPERIMENT 201
WORK, ENERGY AND POWER
GRADE
GRADE
Name: CAYETANO, Ma. Frederiza Anne M.
Program/Year: MSE-2
Course Code/Section: PHY11/B2
Student number: 2010102844
Group number: 2
Date of Performance: July 27, 2013
Date of Submission: August 3, 2013
Sir Bernard Aguirre
Instructor
GRAPH AND CALCULATIONS A. PART 1: DETERMINING THE FORCE, WORK AND POWER OF THE FAN CART
F=wp+wa
W=F∙s
Pave=Wt
where: F = Force of the Fan Cart wp = Weight of Pan wa = weight added W = work done s = displacement t = time Pave = Power computing for F:
wp=5 g1kg1000g∙9.8ms2=0.049 N wa=45 g1kg1000g∙9.8ms2=0.441 N
F=0.049N+0.441N=0.49 N
Trial 1: Given: s=0.3 m t=0.6039 sec
W=F∙s
W=0.49 N∙0.3 m
W=0.147 J
Pave=Wt
Pave= 0.147 N0.6039 sec
Pave=0.243 watts
Trial 2: Given: s=0.4 m t=0.7135 sec
W=F∙s
W=0.49 N∙0.4 m
W=0.196 J
Pave=Wt
Pave= 0.196 N0.7135 sec
Pave=0.275 watts
Trial 3: Given: s=0.5 m t=0.8321 sec
W=F∙s
W=0.49 N∙0.5 m
W=0.245 J Pave=Wt
Pave= 0.245 N0.8321 sec
Pave=0.294 watts
Trial 4: Given: s=0.6 m t=0.9423 sec
W=F∙s
W=0.49 N∙0.6 m
W=0.294 J
Pave=Wt
Pave= 0.294 N0.9423 sec
Pave=0.312 watts
B. PART 2: WORK BY A FORCE ON A CURVED PATH
W=wL1-cosθ
U=mgh where: W = work in moving the mass w = Weight of mass L = length of the string in meters θ = angle of the string with the vertical in degrees U = potential energy g = gravitational acceleration, 9.8ms2 h = height in meters Given: L = 0.20 m w = 500 g1kg1000g⋅9.8ms2=4.9 N h0 = 10.4 cm1 m100 cm=0.104 m m = 500 g1kg1000g=0.5 kg
Trial 1:
Given: θ=10.33° hf=0.106 m h= hf-h0=2×10-3m
W=wL1-cosθ
W=4.9N0.20m1-cos10.33°
W=0.016N
U=mgh
U=0.5 kg9.8ms22×103m
U=9.8×10-3 J
Trial 2:
Given: θ=18.00° hf=0.115 m h= hf-h0=0.011m
W=wL1-cosθ
W=4.9N0.20m1-cos18.00°
W=0.048N
U=mgh
U=0.5 kg9.8ms20.011m
U=0.054 J
Trial 3:
Given:
DEPARTMENT OF PHYSICS
EXPERIMENT 201
WORK, ENERGY AND POWER
GRADE
GRADE
Name: CAYETANO, Ma. Frederiza Anne M.
Program/Year: MSE-2
Course Code/Section: PHY11/B2
Student number: 2010102844
Group number: 2
Date of Performance: July 27, 2013
Date of Submission: August 3, 2013
Sir Bernard Aguirre
Instructor
GRAPH AND CALCULATIONS A. PART 1: DETERMINING THE FORCE, WORK AND POWER OF THE FAN CART
F=wp+wa
W=F∙s
Pave=Wt
where: F = Force of the Fan Cart wp = Weight of Pan wa = weight added W = work done s = displacement t = time Pave = Power computing for F:
wp=5 g1kg1000g∙9.8ms2=0.049 N wa=45 g1kg1000g∙9.8ms2=0.441 N
F=0.049N+0.441N=0.49 N
Trial 1: Given: s=0.3 m t=0.6039 sec
W=F∙s
W=0.49 N∙0.3 m
W=0.147 J
Pave=Wt
Pave= 0.147 N0.6039 sec
Pave=0.243 watts
Trial 2: Given: s=0.4 m t=0.7135 sec
W=F∙s
W=0.49 N∙0.4 m
W=0.196 J
Pave=Wt
Pave= 0.196 N0.7135 sec
Pave=0.275 watts
Trial 3: Given: s=0.5 m t=0.8321 sec
W=F∙s
W=0.49 N∙0.5 m
W=0.245 J Pave=Wt
Pave= 0.245 N0.8321 sec
Pave=0.294 watts
Trial 4: Given: s=0.6 m t=0.9423 sec
W=F∙s
W=0.49 N∙0.6 m
W=0.294 J
Pave=Wt
Pave= 0.294 N0.9423 sec
Pave=0.312 watts
B. PART 2: WORK BY A FORCE ON A CURVED PATH
W=wL1-cosθ
U=mgh where: W = work in moving the mass w = Weight of mass L = length of the string in meters θ = angle of the string with the vertical in degrees U = potential energy g = gravitational acceleration, 9.8ms2 h = height in meters Given: L = 0.20 m w = 500 g1kg1000g⋅9.8ms2=4.9 N h0 = 10.4 cm1 m100 cm=0.104 m m = 500 g1kg1000g=0.5 kg
Trial 1:
Given: θ=10.33° hf=0.106 m h= hf-h0=2×10-3m
W=wL1-cosθ
W=4.9N0.20m1-cos10.33°
W=0.016N
U=mgh
U=0.5 kg9.8ms22×103m
U=9.8×10-3 J
Trial 2:
Given: θ=18.00° hf=0.115 m h= hf-h0=0.011m
W=wL1-cosθ
W=4.9N0.20m1-cos18.00°
W=0.048N
U=mgh
U=0.5 kg9.8ms20.011m
U=0.054 J
Trial 3:
Given: