# Osmosis Lab Report

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Osmosis Lab Report
To what extent does varying the Sodium Chloride concentration impact the mass change of Solanum tuberosum cubes?
Katie Hynek

12/11/15
Personal Engagement:
Every Thanksgiving my aunt and grandma switch off making mashed potatoes and every year they use the same recipe. This year it was my aunt's turn and when we went to eat the mashed potatoes they were super salty. After thanksgiving dinner that year I became interested in figuring out how the using the same recipes the outcome could be so different.

Background Information:
Osmosis is the of a solvent across a semipermeable membrane from an area of lower solute concentration to an area of higher solute concentration. The water being the solvent can move across the membrane but the salt
Shave off pieces of potato until each core has a mass of 3.0 grams
Fill each beaker with 100mL of distilled water at room temperature
Measure out 0.2, 0.4, 0.6, 0.8 grams of salt
Leave beaker one alone, place 0.2 grams of salt in the second beaker, place 0.4 grams of salt in the third beaker, place 0.6 in the fourth beaker, and place 0.8 in the fifth beaker
Use the stirring rod to stir the distilled water and the salt until you can’t see the crystals anymore Place 5 potato cores in each beaker of salt water solution
Leave the potato cores in the solution for five days
Beginning with the beaker of 0.0 g pull one potato core out of the solution and utilization of the electronic balance, determine the mass of each.
Record all data in the raw data table Repeat for all five potato cores and all five
In my case there was significant changes. There was significant changes between the different concentrations.
Average
To calculate average first you have to add up all the number is the 0.0 grams column. After you have the 0.0 grams added up you need to divide by how many numbers in the column. An example is in column 0.0 grams, 4.2+3.1+4.0+3.2+4.3= 18.8. Once you have the total from the column you divide by how many numbers you added together, 18.8/5=3.76. The average is 3.76 for 0.0 grams. You repeat the steps for the rest of the columns.

Standard Deviation
Formula:

X
Average of all 5 concentrations at each level
X-X
The average of all groups added together minus the average of all 5 concentrations at each level
X-X2
The answer that you got from the second to the power of

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