# Nuclear force

ISSN 2224-3577

International Journal of Science and Technology

©2012 IJST. All rights reserved

http://www.ejournalofsciences.org

Nuclear Force

Md. Kamal uddin

At,po—pokhraira, via Birouli(R.I),samastipur(Bihar), India

ABSTRACT

It is well established that the forces between nucleons are transmitted by meson. The quantitative explanation of nuclear forces in terms of meson theory was extremely tentative & in complete but this theory supplies a valuable point of view . it is fairly certain now that the nucleons within nuclear matter are in a state made rather different from their free condition by the proximity of other nucleons charge independence of nuclear forces demand the existence of neutral meson as amongst the same type of nucleolus (P-P) or (N-N). this force demand the same spin & orbital angular momentum. The exchange interaction in produced by only a neutral meson. The involving mesons without electric charge, that it gives exchanges forces between proton & Neutron & also therefore maintains charge in dependence character. It is evident for the nature of the products that neutral mesons decay by strong & weak interaction both. It means that neutral mesons constituents responsible for the electromagnetic interaction. Dramatically neutral mesons plays important role for electromagnetic & nuclear force both.

Keywords: Rest mass energy, Mesons, Differentiation, velocity of light

INTRODUCTION

π-& π0mesons( for symmetrical theory)

It is well established that the forces between

nucleons are transmitted by meson. The quantitative

explanation of nuclear forces in terms of meson

theory was extremely tentative & incomplete, but this

theory supplies a valuable point of view. Yukawa

first pointed out that nuclear force can be explained

by assuming that particle of mass about 200 times

the electron mass(mesons) exist & can be emitted &

absorbed by nuclear particles(neutrons & protons) with

such an assumption a force between nuclear particles

is now obtaining.

dm0 =either mass of π0 mesons or mass of π+ , π-& π0

mesons

Now we have the rest mass energy = m0 c2

Differentiating with respect to r (Inner radius at which

nuclear force comes into play)

m0 = mass of nucleons

m0cdc = rest mass energy of nucleons

dr= Range of nuclear force, which can be calculated

from differentiation of Nuclear radius.( The force

between two nucleons is attractive

for distance

r(radius) greater than dr (range) & is repulsive

otherwise).This strongly suggests & is well proved that

to some degree of approximation the total isotopic

spin T is a constant of the motion & is conserved in

all processes, at least with a high probability.

d(m0c2) = c2dm0 + m0d(c2) = c2dm0 + mo d(c2) .dc

dc= The average velocity of neutron & proton. A large

velocity is used in nuclear disintegration.

dr

dr

c = Velocity of light

= c2dm0

+ 2m0c.dc

dr

dr

dr

dc dr

dr

This force is short range, attractive & along

the line joining the two particles (central force).(The

wide success of this first application of quantum

mechanics to nuclear phenomena gives us confidence

in

general use

of quantum mechanics for the

description of the force between heavy particles in

nuclei.

Where dm0c2 = either rest mass energy of π0

mesons(For neutral theory),or rest mass energy of π+,

2 = multiplicity of interacting particles is given by (2T+1), the isotopic spin has no such meaning for leptons or a

gamma rays

1 = either multiplicity of π0 mesons or π+, π- & π0 mesons (evidence of involving of mesons (all type)

Where T = Vector sum of isotopic spin of proton & proton,

neutron& neutron, neutron & proton The success of

these applications supplies additional support for

the hypothesis of the charge independence & charge

symmetry of nuclear force. As the nuclear interactions

do not extend to very large distances beyond the

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Volume 2 No.2, February 2012...

References: [1] Elementry nuclear theory.H.A.Bathe

[2] Nuclear physics, Roy & Nigam

[3] Nuclear physics, Srivastava

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