Nuclear force

Topics: Neutron, Proton, Atom Pages: 16 (3394 words) Published: December 27, 2013
Volume 2 No.2, February 2012

ISSN 2224-3577

International Journal of Science and Technology

©2012 IJST. All rights reserved

Nuclear Force
Md. Kamal uddin
At,po—pokhraira, via Birouli(R.I),samastipur(Bihar), India

It is well established that the forces between nucleons are transmitted by meson. The quantitative explanation of nuclear forces in terms of meson theory was extremely tentative & in complete but this theory supplies a valuable point of view . it is fairly certain now that the nucleons within nuclear matter are in a state made rather different from their free condition by the proximity of other nucleons charge independence of nuclear forces demand the existence of neutral meson as amongst the same type of nucleolus (P-P) or (N-N). this force demand the same spin & orbital angular momentum. The exchange interaction in produced by only a neutral meson. The involving mesons without electric charge, that it gives exchanges forces between proton & Neutron & also therefore maintains charge in dependence character. It is evident for the nature of the products that neutral mesons decay by strong & weak interaction both. It means that neutral mesons constituents responsible for the electromagnetic interaction. Dramatically neutral mesons plays important role for electromagnetic & nuclear force both.

Keywords: Rest mass energy, Mesons, Differentiation, velocity of light


π-& π0mesons( for symmetrical theory)

It is well established that the forces between
nucleons are transmitted by meson. The quantitative
explanation of nuclear forces in terms of meson
theory was extremely tentative & incomplete, but this
theory supplies a valuable point of view. Yukawa
first pointed out that nuclear force can be explained
by assuming that particle of mass about 200 times
the electron mass(mesons) exist & can be emitted &
absorbed by nuclear particles(neutrons & protons) with
such an assumption a force between nuclear particles
is now obtaining.

dm0 =either mass of π0 mesons or mass of π+ , π-& π0

Now we have the rest mass energy = m0 c2
Differentiating with respect to r (Inner radius at which
nuclear force comes into play)

m0 = mass of nucleons
m0cdc = rest mass energy of nucleons
dr= Range of nuclear force, which can be calculated
from differentiation of Nuclear radius.( The force
between two nucleons is attractive
for distance
r(radius) greater than dr (range) & is repulsive
otherwise).This strongly suggests & is well proved that
to some degree of approximation the total isotopic
spin T is a constant of the motion & is conserved in
all processes, at least with a high probability.

d(m0c2) = c2dm0 + m0d(c2) = c2dm0 + mo d(c2) .dc

dc= The average velocity of neutron & proton. A large
velocity is used in nuclear disintegration.



c = Velocity of light

= c2dm0

+ 2m0c.dc




dc dr


This force is short range, attractive & along
the line joining the two particles (central force).(The
wide success of this first application of quantum
mechanics to nuclear phenomena gives us confidence
general use
of quantum mechanics for the
description of the force between heavy particles in
Where dm0c2 = either rest mass energy of π0
mesons(For neutral theory),or rest mass energy of π+,

2 = multiplicity of interacting particles is given by (2T+1), the isotopic spin has no such meaning for leptons or a
gamma rays
1 = either multiplicity of π0 mesons or π+, π- & π0 mesons (evidence of involving of mesons (all type)
Where T = Vector sum of isotopic spin of proton & proton,
neutron& neutron, neutron & proton The success of
these applications supplies additional support for
the hypothesis of the charge independence & charge
symmetry of nuclear force. As the nuclear interactions
do not extend to very large distances beyond the


Volume 2 No.2, February 2012...

References: [1] Elementry nuclear theory.H.A.Bathe
[2] Nuclear physics, Roy & Nigam
[3] Nuclear physics, Srivastava
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