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Nt1210 Chapter 1

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Nt1210 Chapter 1
CHAPTER 1 INFORMATION TECHNOLOGY1.0 Introduction Information technology (IT) is the design, development, implementation, support, and management of computer hardware and software applications. An IT professional is knowledgeable about computer systems and operating systems. This chapter will review IT certifications and the components of a basic personal computer system.After completing this chapter, you will meet these objectives: * Explain IT industry certifications. * Describe a computer system. * Identify the names, purposes, and characteristics of cases and power supplies. * Identify the names, purposes, and characteristics of internal components. * Identify the names, purposes, and characteristics of ports and cables. * Identify …show more content…
* Voltage is measured in volts (V). A computer power supply usually produces several different voltages. * Current is a measure of the amount of electrons going through a circuit. * Current is measured in amperes, or amps (A). Computer power supplies deliver different amperages for each output voltage. * Power is a measure of the pressure required to push electrons through a circuit, called voltage, multiplied by the number of electrons going through that circuit, called current. The measurement is called watts (W). Computer power supplies are rated in watts. * Resistance is the opposition to the flow of current in a circuit. Resistance is measured in ohms. Lower resistance allows more current, and therefore more power, to flow through a circuit. A good fuse will have low resistance or a measurement of almost 0 ohms.There is a basic equation that expresses how three of the terms relate to each other. It states that voltage is equal to the current multiplied by the resistance. This is known as Ohm's Law.V = IRIn an electrical system, power (P) is equal to the voltage multiplied by the current.P = VIIn an electrical circuit, increasing the current or the voltage will result in higher power.As an example of how this works, imagine a simple circuit that has a 9V light bulb hooked up to a 9V battery. The power output of the light bulb is 100W. Using the equation above, we can calculate how much current in amps would be required to get 100W out of this 9V bulb.To solve this equation, we know the following information: * P = 100W * V = 9V * I = 100W / 9V = 11.11AWhat happens if a 12V battery and a 12V light bulb are used to get 100W of power?100W / 12V = 8.33AThis

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