# Maths

Pages: 6 (266 words) Published: August 19, 2014
Yr 10
Mathematics
Assignment

LCR Maths

1. y = 1.2𝑥 + 2.57
2. Interpolation: y = -3.43
Extrapolation: y = -8.23

a) The equation for the path of the ball is h = -0.1t^2 + 0.9t + 1 (h = height, t = time) b) The vertical height of the ball after 2. seconds2.664m
c) The maximum height reached by the ball is 3.025m
d) The time of with the ball is at maximum height of 3.025 is 4.5 seconds e) The total time in which the ball was in the air is 10 seconds f) The two times in which the ball was 1 metre above ground is 0 and 9

LCR Mathematics

1.

Equation: y = -1.2𝒙2 + 8.4𝒙
a. The bridge is 7 metres wides so therefore it will successfully span the river with 2 metres to spare.
b. If a yacht has a 15 metre mask it will be unable to pass safely under the bridge because the bridge only has a vertical height 14.7 metres.

LCR Mathematics

2. Equation: v= -0.2h2 + 2.4h
a. The horizontal distance covered by the rocket when it reached its maximum height of 7.2 metres was 6 metres.
b. The maximum height reached by the rocket was 7.2 metres.
c. At the horizontal distance of 9 metres from the launch site, there is a 5.2 metre wall and at that vertical distance, the rocket has a vertical distance 5.4 metre. That is not taking to account the dimensions of the rocket, however the rocket cannot have a diameter larger than 20cm otherwise it may not theoretically clear the wall.

LCR Mathematics

3. Equation: y = 𝒙2
Possible values
 a>1
 0