Mean: (Avg) 14.87

Median: (14.87 + 14.87) / 2 = 14.8

Standard Deviation: 0.55033

Construct a 95% Confidence Interval for the ounces in the bottles.

With a mean score of 14.87, a standard deviation of 0.55033, and a desired confidence level of 95%, the corresponding confidence interval is + 0.2. There is a 95% certainty that the true population mean falls within the range of 14.67 to 15.07.

Conduct a hypothesis test to verify if the claim that a bottle contains less than sixteen (16) ounces is supported. Clearly state the logic of your test, the calculations, and the conclusion of your test.

There is a complaint that the bottles of the brand of soda produced in your company contain less than the advertised sixteen (16) ounces of product. In order to verify if the claim that a bottle contains less than sixteen (16) ounces is supported, the employees will pull thirty bottles off the line at random from all the shifts at the bottling plant. Employees are required to measure the amount of soda there is in each bottle.

Alternative hypothesis: the bottles of the brand of soda produced contain less than the advertised sixteen (16) ounces of product

Null hypothesis: the bottles of the brand of soda produced do not contain less than the advertised sixteen (16) ounces of product.

95% Confidence Interval = (14.67,15.07)

In this project we were given the case of customer complaints that the bottles of the brand of soda produced in our company contained less than the advertised sixteen ounces of product. Our boss wants us to solve the problem at hand and has asked me to investigate. I have asked my employees to pull Thirty (30) bottles off the line at random from all the shifts at the bottling plant. The first step in solving this problem is to calculate the mean (x bar), the median (mu), and the standard deviation (s) of the sample. All of those calculations were easily computed in excel. The mean was computed by entering: =average, the