Lab 3: Bromination Of Acetanilide

Lab 3: Bromination of Acetanilide
CHEM 2110
Hassan Alsaleh
0525970
Due date :11/02/2015

Q1:
To find the limiting reagent we need to find the number of moles of acetanilide, and the number of moles of Bromine.

Mass of Acetanilide used = 0.67g
Molar mass of Acetanilide = 135.16g/mol[1]
Number of moles of Acetanilide = (0.67g) / (135.16g/mol) = 0,005 mols

Volume of Bromine = 0.25ml
Density of Bromine = 3.103 g/ml[2]
Mass of Bromine = (0.25ml) X (3.103g/ml) = 0.78g
Molar mass of Bromine = 79.9g/mol[2]
Number of moles of bromine = (0.78g) / (79.9g/mol) = 0,0097 mols

Acetanilide is the limiting reagent

-To find the heoretical yield of p-bromoacetanilide:
Number of moles of p-bromoacetanilide =0,0049 mols
Molar