Kristen’s Cookie Company
OPIM 902 – Operations Management Case Analysis –
Kristen’s Cookie Company
Arif Durak, İlker Koç, Nihat Alpin Mütevellioğlu, Uğur Günal, Ersan Bilik
31 May 2014
1) How long will it take you to fill a rush order?
For an order that is for 1 dozen (or less) cookies with the same ingredients, it takes 26 minutes assuming the customer pays after packing. If they pay during the cooling period, a minute could be saved.
Time (minutes)
Operation
0
Take Order
6
Wash & Mixing
2
Spoon
1
Set Temp/Time
9
Bake
0
Remove from oven
5
Cool
2
Pack
1
Payment
26
Total
2) How many orders can you fill in a night, assuming you are open four hours each night ?
Max # of the orders that can be filled is related with the slowest operation which is baking due to both operation time & oven capacity (bottleneck)
Time (minutes)
Operation
Batch Per hour
6
Mixing
7,50
2
Spoon
1
Set Temp
6,00
9
Bake
5
Cool
12,00
2
Pack
30,00
1
Payment
60,00
Because operations for the next batch could be done in parallel with the current batch, the time required for a number of orders is 26 + 10 * (# orders – 1).
Therefore, for 1 order 26 minutes are required, for 2 orders 36 min.s are required, for 3 orders 46 minutes are required and so forth. (Assuming orders are for a dozen cookies and payment is made after packing)
4 hours = 240 minutes = 26 + 10 * (# orders – 1)
Solving the above equation gives #orders = 22,4 or 22 orders
If we work 6 minutes more, we can complete an extra order to make it 23 orders.
In a different approach, for the first batch you lose 8 minutes for mixing & spooning. Therefore, net time left is 240 – 8 = 232 minutes
Since total baking time is 9+1 = 10 minutes, 232 / 10 = 23,2 rounded down you can bake 23 times remaining 2 more minutes. But cookies had to be cooled, packed and paid for with a total time of 5+2+1=8 meaning we have a
Kristen’s Cookie Company
Arif Durak, İlker Koç, Nihat Alpin Mütevellioğlu, Uğur Günal, Ersan Bilik
31 May 2014
1) How long will it take you to fill a rush order?
For an order that is for 1 dozen (or less) cookies with the same ingredients, it takes 26 minutes assuming the customer pays after packing. If they pay during the cooling period, a minute could be saved.
Time (minutes)
Operation
0
Take Order
6
Wash & Mixing
2
Spoon
1
Set Temp/Time
9
Bake
0
Remove from oven
5
Cool
2
Pack
1
Payment
26
Total
2) How many orders can you fill in a night, assuming you are open four hours each night ?
Max # of the orders that can be filled is related with the slowest operation which is baking due to both operation time & oven capacity (bottleneck)
Time (minutes)
Operation
Batch Per hour
6
Mixing
7,50
2
Spoon
1
Set Temp
6,00
9
Bake
5
Cool
12,00
2
Pack
30,00
1
Payment
60,00
Because operations for the next batch could be done in parallel with the current batch, the time required for a number of orders is 26 + 10 * (# orders – 1).
Therefore, for 1 order 26 minutes are required, for 2 orders 36 min.s are required, for 3 orders 46 minutes are required and so forth. (Assuming orders are for a dozen cookies and payment is made after packing)
4 hours = 240 minutes = 26 + 10 * (# orders – 1)
Solving the above equation gives #orders = 22,4 or 22 orders
If we work 6 minutes more, we can complete an extra order to make it 23 orders.
In a different approach, for the first batch you lose 8 minutes for mixing & spooning. Therefore, net time left is 240 – 8 = 232 minutes
Since total baking time is 9+1 = 10 minutes, 232 / 10 = 23,2 rounded down you can bake 23 times remaining 2 more minutes. But cookies had to be cooled, packed and paid for with a total time of 5+2+1=8 meaning we have a