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Hydrochloric Acid Lab Report

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Hydrochloric Acid Lab Report
In my experiment I have found that 50 millilitres of HCL with 2 grams of sodium chloride had the highest conductivity rate compared to the second most conductive solution, 50 milliliters of vinegar with 2 grams of sodium chloride, and the last conductive solution, 50 milliliters of distilled water with 2 grams of sodium chloride. In my first hypothesis I stated if I added sodium chloride to distilled water, than the overall conductivity will become more conductive than just distilled water, since the sodium chloride will break down into it’s respective ions. I also noted the solution will however be less conductive compared to vinegar and HCL also encompassed in 2 grams of sodium chloride. Judging by my final results and several attempts, I …show more content…
What I found from my data proves my hypothesis to be correct. Since HCL has already a wide amplitude of ions, where the addition of sodium chloride just increases the overall ions in the solution, hence more conductivity; since electrons are moved through ions. What I found through three attempts of finding the average conductivity of HCL is 4978.66666667 µS/cm. Which comparably to the 2 different solvents I chose, is the most conductive. This is because once again, HCL has a wide amplitude of ions and is a strong acid. Where comparing to the conductivity of distilled water to HCL would be evidently HCL. This is because distilled water doesn’t contain ions, hence no movement of electrons, furthermore no conductivity. However since we added sodium chloride, distilled water will have some conductivity but no where near the amount of HCL. Comparing to the conductivity of vinegar to HCL mostly relays on how acidic each other are. Since HCL is a strong acid and vinegar is a weak acid, this will impact how many ions will be readily to convert in their respective ions; which then causes HCL to have a high degree of ionization compared to

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