Hgd Handbook Answers

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Analytical Chemistry
CHEM 2354

Analytical Chemistry
CHM 2354, Winter 2015
Schedule:
Monday LAB

14:30-18:30

Marion Hall (MRN)

Room: 301

Tuesday DGD
Thursday DGD
Thursday LEC
Tuesday LEC

14:30-15:30
14:30-15:30
08:30-10:00
10:00-11:30

HGN
FSS
Montpetit Hall (MNT)
Montpetit Hall (MNT)

Room: 302
Room: 2005
Room: 202
Room: 202

Instructor: Professor Maxim Berezovski
Office:
Address: D’Iorio Hall room 201
Phone: [phone] ext. 1898 e-mail: [e-mail] web page: http://mysite.science.uottawa.ca/mberezov/
Office Hours:
15:30-17:30 Tuesdays & Thursdays (after DGDs) or by Special Appointment
I am in my office many other times during the week and am always willing to speak with you if you find me in or make an appointment.
- Concentrations of gases should be expressed in bars. express gas as Pgas, emphasize pressure instead of concentration
► 1 bar = 105 Pa; 1 atm = 1.01325 bar
►

- Concentrations of pure solids, pure liquids and solvents are omitted
► are unity
► standard

state is the pure liquid or solid

3.) Manipulating Equilibrium Constants
Consider the following reaction:

[ H  ][ A ]
K1 
[ HA]

Reversing the reaction results in a reciprocal equilibrium reaction:

K '1 

[ HA]




[ H ][ A ]

1 / K 1

Chemical Equilibrium
Equilibrium Constant
3.) Manipulating Equilibrium Constants
If two reactions are added, the new K is the product of the two individual K values:

K1
K2
K3

[ H  ][ A ]
K1 
[ HA]

K2 

[CH  ]
[ H  ][C ]

[ A ][CH  ]
K3 
[ HA][C ]

[ H  ][ A ] [CH  ] [ A ][CH  ]
K 3 K1K 2 



[ HA]
[ HA][C ]
[ H ][C ]

Chemical Equilibrium
Equilibrium Constant
3.) Manipulating Equilibrium Constants

Example:
Given the reactions and equilibrium constants:
Kw= 1.0 x 10-14
KNH3= 1.8 x 10-5
Find the equilibrium constant for the reaction:

Solution:
K1=