a. Sheen should stock the optimal stocking quantity in this situation, which is 584 newspapers. The expected profit at this stocking quantity is $331.44. b. Q= µ+Φ-1(Cu/(Cu+C0))δ Q=500+ Φ-1(.8/(.2+.8))100 Q=500+(..7881)(100) Q=579 This is off by 5 newspapers from the model given in the spreadsheet, which results in a $.03 difference in profitsSe ingresa el resultado de la pregunta 1. El cual se resuelve con el siguiente enunciado.

a. Sheen should stock the optimal stocking quantity in this situation, which is 584 newspapers. The expected profit at this stocking quantity is $331.44. b. Q= µ+Φ-1(Cu/(Cu+C0))δ Q=500+ Φ-1(.8/(.2+.8))100 Q=500+(..7881)(100) Q=579 This is off by 5 newspapers from the model given in the spreadsheet, which results in a $.03 difference in profitsSe ingresa el resultado de la pregunta 1. El cual se resuelve con el siguiente enunciado.

a. Sheen should stock the optimal stocking quantity in this situation, which is 584 newspapers. The expected profit at this stocking quantity is $331.44. b. Q= µ+Φ-1(Cu/(Cu+C0))δ Q=500+ Φ-1(.8/(.2+.8))100 Q=500+(..7881)(100) Q=579 This is off by 5 newspapers from the model given in the spreadsheet, which results in a $.03 difference in profitsSe ingresa el resultado de la pregunta 1. El cual se resuelve con el siguiente enunciado.

a. Sheen should stock the optimal stocking quantity in this situation, which is 584 newspapers. The expected profit at this stocking quantity is $331.44. b. Q= µ+Φ-1(Cu/(Cu+C0))δ Q=500+ Φ-1(.8/(.2+.8))100 Q=500+(..7881)(100) Q=579 This is off by 5 newspapers from the model given in the spreadsheet, which results in a $.03 difference in profitsSe ingresa el resultado de la pregunta 1. El cual se resuelve con el siguiente enunciado.

a. Sheen should stock the optimal stocking quantity in this situation, which is 584 newspapers. The expected profit at this stocking quantity is