# Experiment: Finding Spring Constant

**Topics:**Oscillation, Classical mechanics, Elementary mathematics

**Pages:**6 (594 words)

**Published:**May 21, 2014

Name: Diako Mohammed

CEG Number: 08018457

Submission date: 10-03-2014

Determine the time period of a spring mass system suspended vertically and hence show that the time period is directly proportional to mass of the object. The introduction of a report indentifies the experiment to be taken, Importance of the experiment and overall background to better and understand the experiment, which consist of period motion: the period of circular motion is the time it takes to make one complete circle. The other part is simple harmonic motion: the time taken for an oscillation object to complete one full oscillation is called the time period and measured in seconds and the other part is oscillation of a vertical oscillation follows the simple harmonic motion. For more info (www.citycollegiatephysics.com)

*Theory: The time equal to 2 pie square and the root of mass over the average constant T=2square *Equipment needed: *Diagram: Spring

Stand

Different masses

Stop watch

Hooke

*Procedure: the experiment took place in the class with a group of students with the equipments mentioned before with the teachers supervising we took the data and the mathematics rules in this way and methods: 1. We placed one spring on the ring stand.

2. Hanged 5 different mass holders to the other end of the spring stared with 0.1 gram. 3. Pulled the mass down about one centimeter and released the mass to oscillate up and down. 4.Timed the oscillation of the mass for 20 seconds.

5. Each time added 0.1 gram more and repeat it 3 times for each new mass. 6.at the end calculated the period of the oscillation by stopwatch by diving each of the times by 20.

Table (data of t square and m and k)

Mass

Time for 20 Oscillation

Period, T

Time square second square

Average time square

Spring constant, K

0.1

6.7

0.335

0.1225

0.1158

34.091

6.7

0.335

0.1225

6.4

0.32

0.1024

0.2

8.3

0.415

0.1849

0.1751

45.09

8.6

0.43

0.1722

8.2

0.410

0.1681

0.3

9.4

0.47

0.2209

0.2288

51.76

9.5

0.476

0.2256

9.8

0.49

0.2401

0.4

11.1

0.555

0.3080

0.3117

40.66

11.1

0.555

0.3080

11.3

0.565

0.3192

0.5

12.5

0.625

0.3906

0.3948

49.997

12.4

0.620

0.3844

12.8

0.640

0.4096

Average

44.3196

Mass

Time Square

8.Graph

*Analysis: from this graph we can get the slope of the line * The questions about the experiment:

1) Calculate the slope of the curve from the graph:

Answer: 0.831

2) Does the period of a pendulum depend upon the mass? Explain: Answer: yes it does, because with increasing the mass the time will increase as well. 3) According to Eq. (1), the slope of T square vs. m for a spring –mass oscillation is 4. From the measured value of the slope determine k and complete the value to the value determine from the calculated data.

Answer:

Spring constant average: 44.3196

Compare of the value: the slope (0.8907)-0.831 = 0.0597

4) Write down three precautions that you have to take during this experiment. Answer: a) you have to take care of the safety of your self during working on it b) You have to put the equipment on a straight table c) You have to pull down the mass gently and carefully 5) What will be the mass required to have a period of 2.0 seconds? Show your work Answer: T=2square

Mass= 199,0177

6) From the graph calculate the time period if the mass of the object is 125g: Answer: T=2square

T=33.15

11.precaution

: A) you have to take care of the safety of your self during working on it B)...

Please join StudyMode to read the full document