1. Which patient scored the highest on the preoperative CVLT Acquisition? What was his or her T score?

Answer- Patient 3 with a T score of 63

2. Which patient scored the lowest on postoperative CVLT Retrieval? What was this patient's T score?

Answer- Patient 4 with a T score of 23

3. Did the patient in Question 2 have more of a memory performance decline than average on the CVLT Retrieval? Provide a rationale for your answer.

Answer- According to the case study the average drop in CVLT Retrieval was 9.6. Patient 4 had a drop of 44-23 = 21. This is more than twice the average. Hence patient 4 most definitely experienced a greater memory performance decline than the average.

4. What is the mean (X) and standard deviation (SD) for preoperative T score for CVLT Acquisition?

Answer- Using excel the mean can be found by the following formula,

Mean = AVERAGE(44,42,63,46,51,48,42,46,50,42,44,42,45,46,44,46,47) = 46.35

SD = STDEV(44,42,63,46,51,48,42,46,50,42,44,42,45,46,44,46,47) = 5.06

5. Is the preoperative Retrieval T score for Patient 5 above or below the mean for the norm of the group? Provide a rationale for your answer.

Answer- Mean = AVERAGE(51,51,58,44,52,52,44,45,54,41,42,48,60,41,50,44,46) = 48.41.

The mean of the preoperative Retrieval T score from question 4 is 48.41. Patient 5 had a preoperative T score of 52. Hence patient 5’s T score is above the mean.

6. Assuming that the distribution of the preoperative CVLT Retrieval T scores is normal, the middle 68% of the patients had T scores between what two values?

Answer-- SD= (51,51,58,44,52,52,44,45,54,41,42,48,60,41,50,44,46) = 5.73

68% of the values lie within 1 standard deviation of the mean. Therefore the interval is,

(48.41-5.73, 48.41+5.73) = (41.29, 51.41)

7. Assuming that the distribution of scores for the postoperative CVLT Retrieval T scores is normal, the middle 68% of the patients had T scores