top-rated free essay

Ester Hydrolysis

By alexispaws Apr 22, 2013 1098 Words
The Equilibrium Constant of an Ester Hydrolysis Reaction

Abstract:
The results from this experiment show four different Kc equilibrium constants of: .1522 for bottle two, .1853 for bottle three, .2094 for bottle four, and .2678 for bottle five. The average Kc value came out to be .2037 for all four bottles. Purpose:

The purpose of this lab is to determine the equilibrium concentrations of an organic acid, an alcohol, an ester, and water in four bottles with varying measurements of each compound in of the four solutions. Once the concentrations are determined, one is then to discover the Kc, equilibrium constant, of those solutions by dividing the concentrations of alcohol and acid by the concentrations of ester and water. Methods/Procedure:

First begin by mixing up and standardizing a 500mL solution of NaOH to titrate. For each of the six bottles, measure the directed amounts of ester, water, alcohol, and HCl. The bottles of different solutions will be left to come to equilibrium for two weeks. Once the NaOH is standardized, the solutions in the bottles have come to equilibrium, and a molarity is calculated, use the molarity of NaOH to discover how many mols were used to neutralize the solutions in each bottle. Once all of the calculations are complete, use an ICE chart to discover the mols of ester, water, acid, and alcohol at equilibrium to then calculate the Kc for each bottle. After a Kc has been calculated for all bottles, the last step is to determine an average Kc for all of the solutions. Calculations/Results:

Grams of KHP needed:
.7mol x 35ml x 1molKHP x 204gKHP1000ml x 1 x 1molNaOH x 1molKHP=5.00gKHP Grams of NaOH:
.7molNaOH x .500L x 1mol 1L x 1 x 40g~14gNaOH
Mass of dish: 1.80g Mass of bottle 1: 17.1145g Mass of HCl 1: 4.8778g Mass of NaOH 14.0g Mass of bottle 1A: 17.3521g Mass of HCl 1A: 5.2319g Mass of dish: 2.0097g Mass of dish and KHP: 6.0548g Mass of KHP: 5.0378g mL of NaOH used to neutralize KHP: 1. 36.90mL 2. 30.80mL 3. 36.40mL g of KHP: 1. 5.0378g 2. 4.2074g 3. 4.9722g

Molarity of NaOH:
.6690M|
.6689M|
Avg M: .6688M NaOH|
5.0378gKHP x 1molKHP x 1molNaOH x 1 x 1000mL1 x 204.2g x 1molKHP x 36.90mL x 1L=.6686M

mL of NaOH used:
1A: 6.20mL – 24.90mL = 18.70mL|
1: 17.00mL|
2: 60.54mL|
3: 58.60mL|
4: 45.55mL|
5: 40.75mL|

Ethanol: Water:Ethyl Acetate:
Density: .7893g/mL Density: .9982g/mLDensity: .9003g/mL
Molar Mass: 46.07g/molMolar Mass: 18.02g/molMolar Mass: 88.11g/mol mL of solutions in each bottle:
Bottle #| 3M HCl (mL)| H2O (mL)| Ester (mL)| Alcohol (mL)| 1| 5.00| 5.00| 0| 0|
1A| 5.00| 5.00| 0| 0|
2| 5.00| 0| 5.00| 0|
3| 5.00| 1.00| 4.00| 0|
4| 5.00| 3.00| 2.20| 0|
5| 5.00| 2.00| 2.00| 1.00|

Bottles 1 and 1A M HCl:

17.00mLNaOH x .6688molNaOH x 1 molHCl x 11 x 1000ml x 1molNaOH x .005LHCl=2.27MHCL x .005L= .01137molHCl
.01251 molHCl
Average mol HCl of bottles 1 and 1A:
(.01251mol + .01137mol)/2 = .01194molHCl
Mol NaOH for bottles 2-5:

.6688MNaOH x 1L x 60.54mLNaOH1L x 1000mL x 1= .04049molNaOH
.03919molNaOH
.03046molNaOH
.02725molNaOH
Density of HCl:
5.2319gHCl x 11 x 5.00mL=1.046g/mLHCl
Grams of HCl and H2O:
1.046gHCl x 5.00mLH2O1mL=5.230gHCl+H20
Grams of HCl:
.01194molHCl x 36.54gHCl1 mol HCl= .4352gHCl
Grams of HCl and H2O – Grams of HCl:
5.230gHCl+H2O - .4352gHCl = 4.794gH2O from 5.00mL of HCl in bottles 1-5 Grams of H2O made + grams H2O given for bottles 2-5:
4.794gH2O + 0.00mLH2O x .9982gH2O/mL = 4.794gH2O
5.792gH2O
7.789gH2O
6.790gH2O
Grams to mols of H2O for bottles 2-5:
4.794gH2O x 1molH2O1 x 18.02gH2O= .2661molH2O
.3214molH2O
.4322molH2O
.3768molH2O
Mols of ester for bottles 2-5:
5.00mLester x .9003gester x 1mol ester1 x 1mL x 88.11gester= .05109mols ester
.4087mols ester
.02248mols ester
.02044mols ester
Mols of acid for bottles 2-5:
60.54mLNaOH x 1L x .6688molNaOH x 1molacid1 x 1000mL x 1L x 1molNaOH x 1= .04049molacid
.03919molacid
.03046molacid
.02725molacid
Total mols of acid – mols HCl for bottles 2-5:
.04049mol total acid - .01194mol HCl = .02855mol organic acid .02725mol organic acid .01852mol organic acid
.01531mol organic acid
Mols of alcohol for bottle 5:
1.00mLalcohol x .7893galcohol x 1 mol alcohol1 x 1mL x 46.07galcohol= .01713mol alcohol Ice Charts for bottles 2-5:
ESTER (mol)| WATER (mol)| ACID (mol)| ALCOHOL (mol)|
I: .05109| .2661| 0| 0|
C: -.02855| -.02855| -.02855| -.02855|
E: .02254| .2376| .02855| .02855|

ESTER (mol)| WATER (mol)| ACID (mol)| ALCOHOL (mol)|
I: .04087| .3214| 0| 0|
C: -.02725| -.02725| -.02725| -.02725|
E: .01362| .2942| .02725| .02725|

ESTER (mol)| WATER (mol)| ACID (mol)| ALCOHOL (mol)|
I: .02248| .4322| 0| 0|
C: -.01852| -.01852| -.01852| -.01852|
E: .00396| .4137| .01852| .01852|

ESTER (mol)| WATER (mol)| ACID (mol)| ALCOHOL (mol)|
I: .02044| .3768| 0| .01713|
C:-.01531| -.01531| -.01531| .01531|
E: .00513| .3615| .01531| .03244|

Kc for bottles 2-5:
Kc=.02855[.02855].0254[.2376]= .1522
.1853
.2094
.2678
Avg Kc:
.1522 + .1853 +.2094 + .2678 = .8147
.8147/4 = .2037

Discussion:
A known error in this experiment with this data is the mass of hydrochloric acid measured for bottle 1. The mass was below 5 grams (4.8778g) which threw the calculations off. To compensate for the poor data, an average of the two masses of hydrochloric acid was taken, and then the number of moles was found to get a better approximation of what the number of moles should be. Another possible error in this experiment was not having adequate time for the solutions to equilibrium completely. If the solutions had not fully reached equilibrium the equilibrium constant would be off for whichever solutions, if not all, that had not come to equilibrium. The Kc values were all approximately one tenth off of each other. In theory, the Kc values should all be the same which indicates that there is a high probability that the solutions had not fully reached equilibrium. In conclusion, the results would have been closer and more exact had the solutions had more time to come to equilibrium as well as if the mass of hydrochloric acid was closer to where it should have been.

Cite This Document

Related Documents

  • Hydrolysis of Esters-Acid-Mechanism

    ...[pic] |THE MECHANISM FOR THE ACID CATALYSED HYDROLYSIS OF ESTERS | | | |This page looks in detail at the mechanism for the hydrolysis of esters in the presence of a dilute acid | |(such as ...

    Read More
  • Hydrolysis Report

    ...Hydrolysis Report Bile Esculin Hydrolysis, Starch Hydrolysis, UreaHydrolysis, Casein Hydrolysis Hydrolysis Report Introduction Hydrolysis is a chemical reaction that uses water to split complex molecules. The water molecule H2O is split in the mechanism of hydrolysis, hydrogen cations and hydroxide anions. When the enzyme catalyzes it...

    Read More
  • Synthesis of Esters

    ...SYNTHESIS OF ESTERS USING GREEN AND NON-GREEN CHEMISTRY Abstract Esters are a class of organic compounds with the general formula RCOOR’. Ester also contributes the flavor and aromas in fruits and flowers. The esterification reactions will use in the procedure, which are the interaction of a carboxylic acid with an alcohol, aided by an ino...

    Read More
  • Chemistry Lab Report Ester

    ...Title: Preparation and isolation of an Ester Aim: To make an ester and purify it Background Theory: Esters are derived from carboxylic acids and alcohols with the presence of a catalyst. A carboxylic acid contains the -COOH group, and in an ester the hydrogen in this group is replaced by a hydrocarbon group of some kind. Sulfuric acid...

    Read More
  • Lab: Preparation of Esters

    ... Preparation of Esters Introduction Esters are known for their pleasant smells such as perfumes and artificial flavorings in contained labs. They are formed when a carboxylic acid reacts with alcohol and a strong acid such as a catalyst called sulfuric acid (H2SO4) for this lab. The structural formula for esters can be represented as R...

    Read More
  • Preparing Esters by Esterification Method Using Carboxylic Acid to an Alcohol, Which Is 1.0 Ml of Ethanoic Acid to the Ethanol, and Ethanoic Acid to the Propan-1-Ol, Also Adding H2So4 as a Catalyst for the Reaction

    ...Preparing Esters by esterification method using carboxylic acid to an alcohol, which is 1.0 ml of ethanoic acid to the ethanol, and ethanoic acid to the propan-1-ol, also adding H2SO4 as a catalyst for the reaction Abstract: Esters are a group of organic compound, famous for their interesting odours and smells. In this investigation student ...

    Read More
  • Making Soap: Base-Catalyzed Hydrolysis of a Triglyceride

    ... Background: The purpose of this experiment is to demonstrate saponification in order to prepare a simple soap made from a vegetable oil. The emulsifying properties will also be tested in order to demonstrate the reactions that occur in hard and acidic water. The physical properties of the vegetable oil will be compared to a different phys...

    Read More
  • Global And China Rosin Maleic Acid Glycerol Ester Industry 2014 Market Trend, Size, Share, Growth Research Report

    ...Global And China Rosin Maleic Acid Glycerol Ester Industry 2014 Market Research Report The report firstly introduced Rosin Maleic Acid Glycerol Ester basic information included Rosin Maleic Acid Glycerol Ester definition classification application industry chain structure industry overview; international market analysis, China domestic market...

    Read More

Discover the Best Free Essays on StudyMode

Conquer writer's block once and for all.

High Quality Essays

Our library contains thousands of carefully selected free research papers and essays.

Popular Topics

No matter the topic you're researching, chances are we have it covered.