ECT122 Wk5 ILab 2
ECT 122 Week 5 iLab #2
Parts:
Breadboard
DC power supply
Handheld DMM
Test leads
Wire
100 Ω resistor, 220 Ω resistor, 330 Ω resistor, 470 Ω resistor
1. Calculate the quantities listed.
IT:_46.72mA___ I1A:_28.03mA___ I2A:__18.68mA___
I3A:__38.31mA___ I4A:__8.15mA___ VR1:__6.16V___
VR2:__6.16V___ VR3:__3.83V___ VR4:__3.83V___
Ra= R1//R2= 220Ω//330Ω= 132Ω
Rb= R3//R4= 100Ω//470Ω= 82.45Ω= 82Ω
Rt= Ra+Rb= 132Ω+82Ω= 214Ω
It= Vs/Rt= 10V/214Ω= 0.04672 x 10^-3= 46.72mA
Ir1= It x Ra/R1= 46.72mA x 132Ω/220Ω= 28.032mA
Ir2= It x Ra/R2= 46.72mA x 132Ω/330Ω= 0.018688 x 10^-3= 18.68mA
Ir3= It x Rb/R3= 46.72mA x 82Ω/100Ω= 0.03831 x 10^-3= 38.31mA
Ir4= It x Rb/R4= 46.72mA x 82Ω/470Ω= 0.00815 x 10^-3= 8.15mA
Vr1= Ir1xR1= 28.03mA x 220Ω= 6.16V
Vr2=Ir2xR2= 18.68mA x 330Ω= 6.16V
Vr3= Ir3xR3= 38.31mA x 100Ω=3.83V
Vr4= Ir4xR4= 8.15mA x 470Ω= 3.83V
2. Download the Multisim file “Ser_Par2” from Doc Sharing, Week 5. Run the simulation and verify the simulated results are the same as the calculated values. Were the values the same? Yes/No. If no, why?
IT:_-0.047A___ I1A:_27.976mA____ I2A:__18.654mA___
I3A:_38.449mA__ I4A:__8.181mA___ VR1:__6.155V___
VR2:__6.155V___ VR3:__3.845V__ VR4:__3.845V____
Why is IT negative? IT is measuring negative because of the position it is being measured at. The measured is being taken on the current out side of the circuit.
3. Construct the circuit above on the breadboard. Connect the circuit’s input to the power supply and set it to +10 V. Use the handheld DMM to adjust the supply to +10 V. Using the handheld DMM, measure the values below. Remember, to measure current, the DMM must be in series with the resistor. Have the professor verify the circuit before applying power.
IT:_48.5mA___ I1A:__29.04mA__ I2A:__19.46mA__
I3A:__39.86mA_ I4A:__8.58mA____ VR1A:__6.34V__
VR2A:__3.99V__
Does IT read a negative value on the handheld DMM? If so, make it read a positive value. If it reads positive, make it
Parts:
Breadboard
DC power supply
Handheld DMM
Test leads
Wire
100 Ω resistor, 220 Ω resistor, 330 Ω resistor, 470 Ω resistor
1. Calculate the quantities listed.
IT:_46.72mA___ I1A:_28.03mA___ I2A:__18.68mA___
I3A:__38.31mA___ I4A:__8.15mA___ VR1:__6.16V___
VR2:__6.16V___ VR3:__3.83V___ VR4:__3.83V___
Ra= R1//R2= 220Ω//330Ω= 132Ω
Rb= R3//R4= 100Ω//470Ω= 82.45Ω= 82Ω
Rt= Ra+Rb= 132Ω+82Ω= 214Ω
It= Vs/Rt= 10V/214Ω= 0.04672 x 10^-3= 46.72mA
Ir1= It x Ra/R1= 46.72mA x 132Ω/220Ω= 28.032mA
Ir2= It x Ra/R2= 46.72mA x 132Ω/330Ω= 0.018688 x 10^-3= 18.68mA
Ir3= It x Rb/R3= 46.72mA x 82Ω/100Ω= 0.03831 x 10^-3= 38.31mA
Ir4= It x Rb/R4= 46.72mA x 82Ω/470Ω= 0.00815 x 10^-3= 8.15mA
Vr1= Ir1xR1= 28.03mA x 220Ω= 6.16V
Vr2=Ir2xR2= 18.68mA x 330Ω= 6.16V
Vr3= Ir3xR3= 38.31mA x 100Ω=3.83V
Vr4= Ir4xR4= 8.15mA x 470Ω= 3.83V
2. Download the Multisim file “Ser_Par2” from Doc Sharing, Week 5. Run the simulation and verify the simulated results are the same as the calculated values. Were the values the same? Yes/No. If no, why?
IT:_-0.047A___ I1A:_27.976mA____ I2A:__18.654mA___
I3A:_38.449mA__ I4A:__8.181mA___ VR1:__6.155V___
VR2:__6.155V___ VR3:__3.845V__ VR4:__3.845V____
Why is IT negative? IT is measuring negative because of the position it is being measured at. The measured is being taken on the current out side of the circuit.
3. Construct the circuit above on the breadboard. Connect the circuit’s input to the power supply and set it to +10 V. Use the handheld DMM to adjust the supply to +10 V. Using the handheld DMM, measure the values below. Remember, to measure current, the DMM must be in series with the resistor. Have the professor verify the circuit before applying power.
IT:_48.5mA___ I1A:__29.04mA__ I2A:__19.46mA__
I3A:__39.86mA_ I4A:__8.58mA____ VR1A:__6.34V__
VR2A:__3.99V__
Does IT read a negative value on the handheld DMM? If so, make it read a positive value. If it reads positive, make it