Double Displacement Reaction Lab Report

Step 1:

Pb (NO3) 2 (aq) + CaCl2 (aq)  PbCl2 (aq) + Ca (NO3) 2 (aq) (double displacement reaction)

According to the solubility guidelines lead (II) chloride (PbCl2) is a possible precipitate. This is because even though most chlorides are soluble, lead chloride is considered insoluble (p.2, Lesson 17).

Step 2:

PbCl2 ↔ Pb2+ + 2Cl-

Q = [Pb2+] [Cl-] 2

Step 3:

Ksp = 1.2 x 10-5 (from table 17.1, p.5)

Step 4:

V2 = 20.0 mL (volume of Pb (NO3)2) + 45.0 mL (volume of CaCl2) = 65.0 mL

C2 = C1 V1 V2
Looking at lead nitrate solution before being mixed with the calcium chloride solution. The dissociation of Pb (NO3) 2 can be shown as:

Pb (NO3) 2 (aq)  Pb2+ (aq) + 2NO3- (aq)

This equation indicates that one mole of