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UNIVERSITY OF CAMBRIDGE INTERNATIONAL EXAMINATIONS
GCE Advanced Subsidiary Level and GCE Advanced Level
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MARK SCHEME for the May/June 2010 question paper for the guidance of teachers
9702 PHYSICS
9702/41 Paper 4 (A2 Structured Questions), maximum raw mark 100
This mark scheme is published as an aid to teachers and candidates, to indicate the requirements of the examination. It shows the basis on which Examiners were instructed to award marks. It does not indicate the details of the discussions that took place at an Examiners’ meeting before marking began, which would have considered the acceptability of alternative answers. Mark schemes must be read in conjunction with the question papers and the report on the examination.
•
CIE will not enter into discussions or correspondence in connection with these mark schemes.
CIE is publishing the mark schemes for the May/June 2010 question papers for most IGCSE, GCE Advanced Level and Advanced Subsidiary Level syllabuses and some Ordinary Level syllabuses.
Page 2
Mark Scheme: Teachers’ version GCE AS/A LEVEL – May/June 2010 Section A
Syllabus 9702
Paper 41
1
(a) angle (subtended) at centre of circle (by) arc equal in length to radius (b) (i) point S shown below C (ii) (max) force / tension = weight + centripetal force centripetal force = mrω2 15 = 3.0/9.8 × 0.85 × ω2 ω = 7.6 rad s–1
B1 B1 B1 C1 C1 C1 A1 C1 A1 A1 B1 B1 B1 B1 B1
[2] [1]
[4]
2
(a) (i) 27.2 + 273.15 or 27.2 + 273.2 300.4 K (ii) 11.6 K (b) (i) ( is the) mean / average square speed (ii) ρ = Nm/V with N explained so, pV = 1/3 Nm and pV = NkT with k explained so mean kinetic energy / = ½m = 3/2 kT (c) (i) pV = nRT 2.1 × 107 × 7.8 × 10–3 = n × 8.3 × 290 n = 68 mol (ii) mean kinetic energy = 3/2 kT = 3/2 × 1.38 × 10–23 × 290 = 6.0 × 10–21 J (iii) realisation that total internal energy is the total kinetic energy energy = 6.0 × 10–21 × 68 × 6.02 × 1023 = 2.46 × 105 J
[2]
UNIVERSITY OF CAMBRIDGE INTERNATIONAL EXAMINATIONS
GCE Advanced Subsidiary Level and GCE Advanced Level
e ap .c rs om
MARK SCHEME for the May/June 2010 question paper for the guidance of teachers
9702 PHYSICS
9702/41 Paper 4 (A2 Structured Questions), maximum raw mark 100
This mark scheme is published as an aid to teachers and candidates, to indicate the requirements of the examination. It shows the basis on which Examiners were instructed to award marks. It does not indicate the details of the discussions that took place at an Examiners’ meeting before marking began, which would have considered the acceptability of alternative answers. Mark schemes must be read in conjunction with the question papers and the report on the examination.
•
CIE will not enter into discussions or correspondence in connection with these mark schemes.
CIE is publishing the mark schemes for the May/June 2010 question papers for most IGCSE, GCE Advanced Level and Advanced Subsidiary Level syllabuses and some Ordinary Level syllabuses.
Page 2
Mark Scheme: Teachers’ version GCE AS/A LEVEL – May/June 2010 Section A
Syllabus 9702
Paper 41
1
(a) angle (subtended) at centre of circle (by) arc equal in length to radius (b) (i) point S shown below C (ii) (max) force / tension = weight + centripetal force centripetal force = mrω2 15 = 3.0/9.8 × 0.85 × ω2 ω = 7.6 rad s–1
B1 B1 B1 C1 C1 C1 A1 C1 A1 A1 B1 B1 B1 B1 B1
[2] [1]
[4]
2
(a) (i) 27.2 + 273.15 or 27.2 + 273.2 300.4 K (ii) 11.6 K (b) (i) ( is the) mean / average square speed (ii) ρ = Nm/V with N explained so, pV = 1/3 Nm and pV = NkT with k explained so mean kinetic energy / = ½m = 3/2 kT (c) (i) pV = nRT 2.1 × 107 × 7.8 × 10–3 = n × 8.3 × 290 n = 68 mol (ii) mean kinetic energy = 3/2 kT = 3/2 × 1.38 × 10–23 × 290 = 6.0 × 10–21 J (iii) realisation that total internal energy is the total kinetic energy energy = 6.0 × 10–21 × 68 × 6.02 × 1023 = 2.46 × 105 J
[2]