By calculating the difference in the mass of the hydrate copper (II) sulfate and the anhydride we were able to determine the mass of water in the hydrate. This information was then used to determine the empirical formula of the hydrate, defined as a compound formed by the addition of water to another molecule. In the first trial, the mass of water in the hydrate was determined to be 0.41 g, while in the second trial the mass of water was 0.52 g. Moles of water associated with a single mole of anhydride were then calculated for both trials, giving the values of 4.7 and 4.5 moles of water, respectively. This indicated that the empirical formula of the hydrate might be copper (II) sulfate pentahydrate – CuSO4·5H2O.…
The mass percent of water was determined using the mass of water and dividing it by the total mass of the hydrate and then multiplying that answer by 100%. The number of moles of water in a hydrate was determined by taking the mass of the water released and dividing it by the molar mass of water. The number of moles of water and the number of moles of the hydrate was used to calculate the ratio of moles of water to moles of the sample. This ratio was then used to write the new and balanced equation of the dehydration process. The sample was then rehydrated to the original state and the percent of the hydrate recovered was calculated by using the mass of the rehydrated sample by the mass of the original hydrate and then multiplied by 100%.…
2. Add 2-3 g of sodium hydrogen carbonate to the evaporating dish. Measure the mass of the sodium hydrogen…
[ print page ]03.09 Molar Mass of Compounds: Determining the Formula of a Hydrate—Text Version…
The purpose of this experiment is to determine the formula of a copper sulfate hydrate by heating it up.…
Results: According to our results anhydrous salt magnesium has a formula hydrate of MgSO4 + 7H2O. The average moles of water per mole of anhydrous salt obtained: 6.93 moles. This was the average between trial 1 and trial 2. Even though our samples were not measures exactly even we obtained the same results for trail 1 and 2 for the percent of water in the hydrate =51% and percent of anhydrous salt in the hydrate =49%. The mass of hydrate in trial 1 =3.227g and trial 2 =1.973g. The mass of anhydrous salt trial 1 =1.581g and trial 2 =0.972g. Mass of water liberated trial 1 =1.646g and trial 2 =1.001g. Moles of anhydrous salt in 100g of hydrate trial 1 =0.407moles and trial 2 =0.807 moles. Moles of water in 100g of hydrate trial 1 =2.83 moles and trial =2 5.58 moles. Moles of…
The purpose of this lab was to determine the percent cobalt and oxalate by mass, and with that information, the empirical formula for cobalt oxalate hydrate, using the general formula Coa(C2O4)b.cH2O.…
3. After this, the crucible and crucible cover were allowed to cool and were massed.…
(1) Metric ruler with centimeter (cm) and millimeter (mm), (1) table salt, (1) small number of ice cubes, (1) piece of string, (1) isopropyl (rubbing) alcohol, (1) tap water, (1) distilled water, 25 mL, (1) paper, 5 cm x 5 cm for weighing chemicals, (1) colored drink, (1) beaker, 100 mL, glass (1) burner-fuel, (1) burner-stand, (1) cylinder, 25 mL, (1) 23-mL volumetric flask, (1) Pipet, Serological 2mL, (1) Bulb, Rubber (1) Goggles-Saftey, (1) Scale-Digital-500g, (1) Test Tube (1), 13 x 100 mm, (1) Thermometer, (1) Bolt, (1) Magnet bar, (1) Pipet, Empty Short Stem…
The lab in which we conducted last Tuesday was an analysis of a hydrate and what happens to it when it is heated. A hydrate is a crystalline compound which water molecules are chemically bound to it. In the lab, we were to analyze the difference in grams of the hydrate and the anhydrate. An anhydrate is the crystalline compound without the water molecules bound to it. During our lab, we were to heat up the crucible, the crucible with hydrate, and the crucible with an anhydrous and write down each weight, then repeat. Once we completed that task then we were to find the number of moles of water lost, the number of moles of anhydrous copper sulfate, percent comp of water in the hydrated copper sulfate, the mole ratio of moles of water and moles of anhydrous copper sulfate. Once this is all done, we found our percent error and compared it to the exact value.…
The percent of any compound or element can be found by using a certain formula. This formula is: % of element = Mass of element or compound/Total mass of compound x100. In order to use this formula the mass of the water and the total mass of the hydrate had to be found. The lab workers…
Then from this number the amount of water that was in lost was measured at 1.1 g. After this then the number of moles of anhydrous were calculated from the molar mass of anhydrous. Then the moles of water were calculated. Then the stoichiometric coefficients for each component were calculated. The results found that there was two moles of anhydrous and 35 for water. Thus the empirical formula was found to be:…
The purpose of the Formula of an Unknown Hydrate lab is to determine the weight percentage of H2O hydrated to an unknown salt and the empirical formula for the hydrated salt. To do this, a massed amount of the hydrate is heated over either a hot plate or Bunsen burner. This causes the water to be removed, leaving the anhydrous salt behind in the dish. The mass of the anhydrous salt, now with the absence of water, is less than the original mass of the hydrate. The difference between the two is the mass of the water removed from the hydrate. As shown in data table 1, the mass of the anhydrous salt is 2.66 grams, and the mass of the water removed is .51 grams. The water of hydration was calculated to be about 2. Based on these measurements, the empirical formula of the hydrate is BaCl2 • 2H2O. This means that for every mole of BaCl2, there is about two moles of water. The weight percentage of water to hydrate is about14.75%. This means that in the total mass of BaCl2 • 2H2O, water makes up about 14.75%.…
3. Procedure: In order to perform this lab I needed the following materials: a metric ruler, table salt, small number of ice cubes, piece of string, flame source, rubbing alcohol, tap water, distilled water, paper, colored liquid drink, 100mL glass beaker, burner-fuel, burner-stand, 25 mL cylinder, 25mL volumetric flask, 2mL pipet, rubber bulb, goggles, 500g digital scale, test tube measuring 13x100mm, thermometer, small bolt, magnet bar, and an empty short stem pipet. To start off this lab assignment I measured the length of three objects in centimeters and millimeters with a metric ruler. I measured a knife, lighter, and a standard pack of UNO cards. I recorded the data. Next, I measured the temperature of hot water, boiling water, and boiling water after 5 minutes in Celsius. Then I proceeded to measure the temperature of cold water, ice water, and ice water after 5 minutes. I recorded this data. For this I used my 100mL beaker and hot water. I then used the wire gauze burner stand and the fuel burner in order to bring the water to boil. I measure the temperatures with my thermometer. I then let the beaker cool and measure cold water from the tap and then added ice cubes to the water in order to measure ice water’s temperature with the thermometer. Next, I measure the volume of a test tube by filling the test tube with water and pouring the water into my 25mL graduated cylinder. I recorded this volume. I then filled the pipet with one mL of water and counted how many drops were inside the pipet. I recorded this data. After doing so I…
In this lab, we used Bunsen burners to heat up a hydrated salt in order to determine the percentage of water inside of this hydrated salt. We heated up the salt in order to boil off the water, which allowed us to find the weight of the CuSO4 by itself. By comparing this final weight with the original weight and subtracting the difference, we were able to compile data about how much the weight of the hydrated salt decreased as the water gradually boiled away. In doing so, we were able to find the total weight of the water in the hydrated salt by subtracting the final weight weight from the original weight of the hydrated salt, allowing us to calculate the percentage of water in the hydrated salt by dividing the weight of the water by the original…