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Chapter 2 Solutions Section 2.1 Introduction 2.1 Current source 2.2 Voltage source 2.3 Resistor 2.4 Capacitor 2.5 Inductor Section 2.2 Charge and Current 2.6 b) The current direction is designated as the direction of the movement of positive charges. 2.7 The relationship of charge and current is t q(t ) = ! i(t ) + q(t 0 ) dt t0 so t q(t ) = ! 2 sin ( " t ) + q(t0 ) 10 dt t0 & '2 # q(t )= $ cos( ( t )! + q(t0 ) 10 " t0 %10(
2.8 The coulomb of one electron is denoted by e and t t
q(t ) = ! i (t ) + q(t0 ) dt t0 So
1 n(t ) = q (t ) / e = ! 12t dt + q(t 0 ) e t0
If t0 = 0 and q(t 0 ) = 0 ,
6 n(t ) = t 2 e
t
2.9
© 2013 Pearson Education, Inc., Upper Saddle River, NJ. All rights reserved. This publication is protected by Copyright and written permission should be obtained from the publisher prior to any prohibited reproduction, storage in a retrieval system, or transmission in any form or by any means, electronic, mechanical, photocopying, recording, or likewise. For information regarding permission(s), write to: Rights and Permissions Department, Pearson Education, Inc., Upper Saddle River, NJ 07458.
q(t ) = ! idt t q(t )= ! 5dt
0
q(t ) = 5t
2.10
q(t )= 0 [ t ]= 5(5)! 5(0 ) = 25 Coulombs 5
5
2.11 Using the definition of current-charge relationship, the equation can be rewritten as: i= dq !n = e dt !t
Thus, the current flow within t1 and t2 time interval is,
(5.75 ! 2) " 1019 i= (!1.6 " 10 !19 ) = !3 A 2
The
Chapter 2 Solutions Section 2.1 Introduction 2.1 Current source 2.2 Voltage source 2.3 Resistor 2.4 Capacitor 2.5 Inductor Section 2.2 Charge and Current 2.6 b) The current direction is designated as the direction of the movement of positive charges. 2.7 The relationship of charge and current is t q(t ) = ! i(t ) + q(t 0 ) dt t0 so t q(t ) = ! 2 sin ( " t ) + q(t0 ) 10 dt t0 & '2 # q(t )= $ cos( ( t )! + q(t0 ) 10 " t0 %10(
2.8 The coulomb of one electron is denoted by e and t t
q(t ) = ! i (t ) + q(t0 ) dt t0 So
1 n(t ) = q (t ) / e = ! 12t dt + q(t 0 ) e t0
If t0 = 0 and q(t 0 ) = 0 ,
6 n(t ) = t 2 e
t
2.9
© 2013 Pearson Education, Inc., Upper Saddle River, NJ. All rights reserved. This publication is protected by Copyright and written permission should be obtained from the publisher prior to any prohibited reproduction, storage in a retrieval system, or transmission in any form or by any means, electronic, mechanical, photocopying, recording, or likewise. For information regarding permission(s), write to: Rights and Permissions Department, Pearson Education, Inc., Upper Saddle River, NJ 07458.
q(t ) = ! idt t q(t )= ! 5dt
0
q(t ) = 5t
2.10
q(t )= 0 [ t ]= 5(5)! 5(0 ) = 25 Coulombs 5
5
2.11 Using the definition of current-charge relationship, the equation can be rewritten as: i= dq !n = e dt !t
Thus, the current flow within t1 and t2 time interval is,
(5.75 ! 2) " 1019 i= (!1.6 " 10 !19 ) = !3 A 2
The