# Causes of Health Problem

JABATA PELAJARA MELAKA

PEPERIKSAA SELARAS AKHIR TAHU TI GKATA 4, 2011

MATHEMATICS

Paper 1 One hour and fifteen minutes

DO OT OPE THIS QUESTIO PAPER U TIL YOU ARE TOLD TO DO SO 1. This question paper consists of 40 questions. 2. Answer all questions. 3. Answer each question by blackening the correct space on the answer sheet. 4. Blacken only one space for each question. 5. If you wish to change your answer, erase the blackened mark that you have done. Then blacken the space for the new answer . 6. The diagrams in the questions provided are not drawn to scale unless stated. 7. A list of formulae is provided on pages 2 and 3. 8. You may use a non-programmable scientific calculator.

This question paper consists of 28 printed pages

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2 MATHEMATICAL FORMULAE

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The following formulae may be helpful in answering the questions. The symbols given are the ones commonly used. RELATIO S 1 2 3 4 a m × a n = a m+ n a m ÷ a n = a m−n

(a m ) n = a mn

A −1 =

1 d − b ad − bc − c a

n( A) n (S )

5 6

7

P ( A) =

P ( A' ) = 1 − P( A)

Distance = ( x 2 − x1 ) 2 + ( y 2 − y1 ) 2

8

x1 + x 2 y1 + y 2 , Midpoint , ( x, y ) = 2 2 Average speed =

9

distance travelled time taken

10

Mean = Mean =

sum of data number of data

11 12

sum of(class mark × frequency) sum of frequencie s

Pythagoras Theorem c2 = a2 + b2

13

m=

y 2 − y1 x 2 − x1

14

m=−

y − int ercept x − int ercept

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3

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SHAPES A D SPACE

1 2 3 4 5 6 7 8

Area of trapezium =

1 × sum of parallel sides × height 2

Circumference of circle = πd = 2πr

2 Area of circle = πr

Curved surface area of cylinder = 2πrh

2 Surface area of sphere = 4πr

Volume of right prism = cross sectional area × length Volume of cylinder = πr 2h Volume of cone = 1 2 πr h 3 4 3 πr 3 1 × base area × height 3

9

Volume of sphere =

10 11 12

Volume of right pyramid =

Sum of interior angles of a polygon = (n – 2) × 180º arc length angle subtended at centre = circumference of circle 360 o area of sector angle subtended at centre = area of circle 360 o Scale factor, k = PA' PA

13

14 15

Area of image = k2 × area of object

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4 Answer all questions.

Jawab semua soalan.

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1

Round off 3.028 correct to three significant figures. Bundarkan 3.028 betul kepada tiga angka bererti. A 3.02 B 3.03 C 3.020 D 3.030 Given that 0.000 078 = m x 10n , where m x 10n is a number in standard form. State the value of m and of n. Diberi bahawa 0.000 078 = m x 10n, dengan keadaan m x 10n adalah nombor dalam bentuk piawai. yatakan nilai m dan nilai n. A m = 7.8, n = − 5 B m = 7.8, n = 5 C m = 78, n = − 6 D m = 78, n = 6 0.078 = 2.6 × 10 5 A 3 x 10-3 B 3 x 10-4 C 3 x 10-6 D 3 x 10-7

2

3

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5

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The total population of Malaysia in the year 2010 is 26.37 million. It is given that the number of people who are 60 years of age and above is 4.2% of the total population. Calculate the number of people who are below 60 years of age. [1 million = 106] Jumlah populasi Malaysia dalam tahun 2010 ialah 26.37 juta. Diberi bahawa bilangan orang yang berumur 60 tahun dan ke atas adalah 4.2% daripada jumlah populasi. Hitung bilangan orang yang berumur di bawah 60 tahun. [ I juta = 106 ] A 1.11 x 106 B 1.11 x 107 C 2.53 x 106 D 2.53 x 107

5

Evaluate: ilaikan: 8.32 x 10-5 – 7.6 x 10-6 .

A B C D 6

7.56 x 10-6 8.56 x 10-6 7.56 x 10-5 8.56 x 10-5

(2x – y)2 – x(x + y) = A 3x2 – y2 – 3xy B 3x2 + y2 – 3xy C 3x2 – y2 – 5xy D 3x2 + y2 – 5xy

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6

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7 In Diagram 7, HIJKLM is a regular hexagon. JKLO is a rhombus and JL is the diagonal of the rhombus....

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