Bluej Menu Driven Program

Menu Driven BlueJ Program on Odd, Even and Perfect Numbers

The question here is that, Write a BlueJ program which will ask the user to enter a choice and based on the choice the following operation will take place. if choice=1; then sum of even nos. from the series of 10 nos. if choice=2; then sum of odd nos. from a series of 10 nos. if choice=3; then it will check whether the no is perfect or not from a series of 10 nos.

Codes of the Menu driven BlueJ Program

import java.io.*; class Menu
{
BufferedReader br; int arr[]=new int[10]; public static void main(String args[])throws IOException { Menu ob=new Menu (); ob.accept(); } Menu () { br=new BufferedReader(new InputStreamReader(System.in)); } public void accept()throws IOException
{
int choice; for(int i=0;i<10;i++)
{
System.out.println("Enter number:"); arr[i]=Integer.parseInt(br.readLine().trim());
}
System.out.println("Enter Your Choice (1 for adding even numbers, 2 for adding odd number and 3 for checking perfect number:"); choice=Integer.parseInt(br.readLine().trim()); if(choice==1) addEven(); else if(choice==2) addOdd(); else if(choice==3) showPerfect(); else
System.out.println("Wrong Choice:");
}
private void addEven()
{
int sum=0; for(int i=0;i<10;i++) { if(arr[i]%2==0) sum=sum+arr[i]; } System.out.println("Sum of Even Numbers="+sum);
}

private void addOdd()
{
int sum=0; for(int i=0;i< 10;i++) { if(arr[i]%2!=0) sum=sum+arr[i]; } System.out.println("Sum of Odd Numbers="+sum);
}
private void showPerfect()
{
int sum; for(int i=0;i<10;i++) { sum=0; for(int j=1;j< arr[i];j++) { if(arr[i]%j==0) sum=sum+j; } if(sum==arr[i]) System.out.println(arr[i]+ " is a Prefect Number");
}
}
}

Sample input and output of the BlueJ program

Enter number:
22
Enter number:
4
Enter number:
35
Enter number:
4
Enter number: