Biology IA 1
Ellen Ryan
Biology IA
Task G1
Investigation into the biodiversity of organisms at different heights on a rocky shore.
PART (1)
Ellen Ryan
Introduction
This experiment was carried out in order to better understand Hong Kong’s ecology and biodiversity, specifically focusing on field-based whole organism biology in an area with little human interferences.
Method
1. Lay a horizontal transect on the mid-shore (1.75m)
2. Repeat for high-shore (2.25m)
3. At regular intervals of 1m on one of the transects record the number and species of each organism found within that quadrat.
4. Repeat at the same interval for the other transect.
5. Repeat at each interval.
Conclusion
Based on the data I have collected, I conclude that there is a greater biodiversity on the mid shore than the high shore. This can be demonstrated by a Simpson’s diversity index calculation.
It is only natural that we refer to Simpsons Siversity Index in order to address the investigation at hand. Simpson’s Diversity Index
High Shore
Species
Number (n)
n(n-1)
Monodonta labio
18
306
Lunella coronata
1
0
Echinolittorina trochoides
330
108570
Echinolittorina radiata
146
21170
Planaxis sulcatus
15
210
Notoacmea sp.
34
1122
Cellana toreuma
1
0
Capitulum mitella
113
12656
Total
658
144034
D = 144034/432306 = 0.333
Simpsons Index of Diversity = 1 - D
1 - 0.333 = 0.666
Mid Shore
Ellen Ryan
Species
Number (n)
n(n-1)
Thais clavigera
6
30
Monodonta labio
71
4970
Lunella coronata
3
6
Echinolittorina trochoides
8
56
Echinolittorina radiata
1
0
Echinolittorina vidua
11
110
Planaxis sulcatus
101
10100
Notoacmea sp.
1
0
Monodonta nematoides
14
182
Grapsus albolineatus
1
0
Total
217
15454
Diversity = 15454/46872 = 0.329
Simpsons Index of Diversity = 1 - D
1-0.329 = 0.671
What can be
Biology IA
Task G1
Investigation into the biodiversity of organisms at different heights on a rocky shore.
PART (1)
Ellen Ryan
Introduction
This experiment was carried out in order to better understand Hong Kong’s ecology and biodiversity, specifically focusing on field-based whole organism biology in an area with little human interferences.
Method
1. Lay a horizontal transect on the mid-shore (1.75m)
2. Repeat for high-shore (2.25m)
3. At regular intervals of 1m on one of the transects record the number and species of each organism found within that quadrat.
4. Repeat at the same interval for the other transect.
5. Repeat at each interval.
Conclusion
Based on the data I have collected, I conclude that there is a greater biodiversity on the mid shore than the high shore. This can be demonstrated by a Simpson’s diversity index calculation.
It is only natural that we refer to Simpsons Siversity Index in order to address the investigation at hand. Simpson’s Diversity Index
High Shore
Species
Number (n)
n(n-1)
Monodonta labio
18
306
Lunella coronata
1
0
Echinolittorina trochoides
330
108570
Echinolittorina radiata
146
21170
Planaxis sulcatus
15
210
Notoacmea sp.
34
1122
Cellana toreuma
1
0
Capitulum mitella
113
12656
Total
658
144034
D = 144034/432306 = 0.333
Simpsons Index of Diversity = 1 - D
1 - 0.333 = 0.666
Mid Shore
Ellen Ryan
Species
Number (n)
n(n-1)
Thais clavigera
6
30
Monodonta labio
71
4970
Lunella coronata
3
6
Echinolittorina trochoides
8
56
Echinolittorina radiata
1
0
Echinolittorina vidua
11
110
Planaxis sulcatus
101
10100
Notoacmea sp.
1
0
Monodonta nematoides
14
182
Grapsus albolineatus
1
0
Total
217
15454
Diversity = 15454/46872 = 0.329
Simpsons Index of Diversity = 1 - D
1-0.329 = 0.671
What can be