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I. (19 points)
A. Aziridines are 3-membered nitrogen heterocycles that can behave as electrophiles in substitution reactions.
The aziridine 1 shown below has been shown to react with Na+ –OCH3 to give products 2 and 3.
Ph =
Note:
Na
N
OCH3
Br
N
+
N
OCH3
3
2
1
This abbreviation has been used in the scheme below. You may also use this abbreviation when drawing
Newman projections on page 5.
OCH3
(a) The formation of product 3 occurs via (i) reaction between CH3O– and the more substituted carbon of aziridine 1 to generate intermediate 4; (ii) intramolecular nucleophilic substitution to generate product 3.
Provide the structure of intermediate 4 and draw curved arrows showing the …show more content…
The ratio of 8 and 9 depends on the type of base that is used.
H
O
H
H
O
CH3 +
Li
H
B
Li
CH3
+ HB
H
H
Li
O
CH3
+
+ HB
2-methylcyclohexanone
Note: B is a generic base and HB is its conjugate acid.
Specific bases are given in parts b and c below. 8
9
(a) Based on the information provided below, construct an energy diagram for the conversion of
2-methylcyclohexanone + base (SM) to products 8 and 9 . On your diagram, clearly show the position of products 8 and 9, transition states A and B, and draw the appropriate energy curves.
SM
• The reaction occurs in a single step.
No intermediates are formed
• The conversion of SM to 8 proceeds through transition state A.
• The conversion of SM to 9 proceeds through transition state B.
!G° for SM
!G° for SM
!G‡ (EA) SM
!G‡ (EA) SM
2 kcal/mol
B
A
!G
(kcal/mol)
SM
8: –2 kcal/mol
9: –4 kcal/mol
A: +4 kcal/mol
B: +8 kcal/mol
8
9
Progress of Reaction
(b) When Li+ –N[CH(CH3)2]2 is used as a base, the product ratio is controlled by reaction kinetics. Which is the major product under these conditions (circle one