Avogadro's Number Lab Report
CHEMISTRY I
Experiment 12: Avogadro's number (hand out)
Introduction:
The objective of this experiment is to determine the value of Avogadro's number and the mole concept via the use of the monolayer experiment.
Experimental data sheet: Attached
Calculations:
1. Area of monolayer
A= 3.14(8.58 cm)² / 4
A= 231 cm² / 4
A = 57.8 cm²
2. Molecules of stearic acid in monolayer
57.8 cm² x 1molecule = 2.8 x 1016 molecules 2.1 x 10-15 cm²
3. Moles of stearic acid in monolayer
Average drops of stearic acid to make up the monolayer = 6 Average drops of stearic solution in 1 mL = 96
ml of stearic acid in monolayer = 6 / 96 = .0625 ml …show more content…
Grams of stearic acid in monolayer = .1ml x 1.4 x 10 -4 g ml = 1.4 x 10 -5 g
1.4 x 10 -5 gram stearic acid x 1mol stearic acid = 4.9 x10-8 mol stearic acid 284 g stearic acid
Avogadro's number = 2.8 x1016 molecules = 5.7 x 10 23 molecules/moles 4.9 x 10 -8 mol
Analysis/Discussion:
Experiment 12: Avogadro's number (hand out)
Introduction:
The objective of this experiment is to determine the value of Avogadro's number and the mole concept via the use of the monolayer experiment.
Experimental data sheet: Attached
Calculations:
1. Area of monolayer
A= 3.14(8.58 cm)² / 4
A= 231 cm² / 4
A = 57.8 cm²
2. Molecules of stearic acid in monolayer
57.8 cm² x 1molecule = 2.8 x 1016 molecules 2.1 x 10-15 cm²
3. Moles of stearic acid in monolayer
Average drops of stearic acid to make up the monolayer = 6 Average drops of stearic solution in 1 mL = 96
ml of stearic acid in monolayer = 6 / 96 = .0625 ml …show more content…
Grams of stearic acid in monolayer = .1ml x 1.4 x 10 -4 g ml = 1.4 x 10 -5 g
1.4 x 10 -5 gram stearic acid x 1mol stearic acid = 4.9 x10-8 mol stearic acid 284 g stearic acid
Avogadro's number = 2.8 x1016 molecules = 5.7 x 10 23 molecules/moles 4.9 x 10 -8 mol
Analysis/Discussion: