Aspirin: Acetylsalicylic Acid
Aspirin analysis
Introduction
Aspirin, which is also known as acetylsalicylic acid. C9H8O4 is the chemical format for Asprin.
The chemical structure of aspirin:
Aspirin is anti-inflammatory. Aspirin is prepared by chemical synthesis from salicylic acid, by acetylation with acetic anhydride. The fact that it is an acid allows us to quantify the amount of aspirin in a solution. We would do this by by using an acid-base titration. Sodium hydroxide (NaOH) will be used In this experiment as the base.
Preparation
• Lab coats should be fully fastened at all times.
• Gloves and safety goggles should be worn at all times.
Method
In all titration experiments careful measurements are very essential in order to gain accurate results.
1. Firstly fill the burette …show more content…
Lastly, record the volume of the sodium hydroxide used on the table.
10. Repeat this procedure twice for each tablet type.
Results Assay 1 Assay 2 Assay 3
Mass of tube + aspirin (g) 2.76g 2.77 g 2.75 g
Mass of tube (g) 2.46g 2.46 g 2.46 g
Mass of aspirin (g) 0.3g 0.31 g 0.29 g
Initial burette reading (cm3) 20cm3 32.6 cm3 37.5 cm3
Final burette reading (cm3) 32.6cm3 47.5 cm3 47.8 cm3
Volume of NaOH added (cm3) 0.0126L 0.0149 L 0.0103 L
Amount of NaOH added (mol) 0.00126 mol 0.00149 mol 0.00103 mol
Amount of aspirin reacted (mol) 0.00126 mol 0.00149 mo; 0.00103 mol
Mass of aspirin reacted (g) 0.2268 g 0.2682 g 0.1854g
Aspirin in powder (% w/w) 75.6% 86.5% 63.9%
Calculation format experiment
Mass of tube + asprin – mass of tube = mass of asprin per g
2.76 g – 2.46 g + 0.3g
Final burette reading – initial burette reading = volume of NaOH added
32.6 cm3 – 20 cm3 = 12.6 cm3
Volume of NaOH x 0.1 mol = amount of NaOH added
e.g
0.0120 L x 0.1 mol = 0.00126 mol
Amount of asprin = 0.00126 mol
Carbon = 9 x 12
Hydrogen = 8 x 1 180
Oxygen = 4 x 16
180 x 0.00126 = 0.23 mass of reaction
Aspirin powder
0.2268g / 0.3 (mass of asprin) = 0.756
0.756 x 100 =75.6
Introduction
Aspirin, which is also known as acetylsalicylic acid. C9H8O4 is the chemical format for Asprin.
The chemical structure of aspirin:
Aspirin is anti-inflammatory. Aspirin is prepared by chemical synthesis from salicylic acid, by acetylation with acetic anhydride. The fact that it is an acid allows us to quantify the amount of aspirin in a solution. We would do this by by using an acid-base titration. Sodium hydroxide (NaOH) will be used In this experiment as the base.
Preparation
• Lab coats should be fully fastened at all times.
• Gloves and safety goggles should be worn at all times.
Method
In all titration experiments careful measurements are very essential in order to gain accurate results.
1. Firstly fill the burette …show more content…
Lastly, record the volume of the sodium hydroxide used on the table.
10. Repeat this procedure twice for each tablet type.
Results Assay 1 Assay 2 Assay 3
Mass of tube + aspirin (g) 2.76g 2.77 g 2.75 g
Mass of tube (g) 2.46g 2.46 g 2.46 g
Mass of aspirin (g) 0.3g 0.31 g 0.29 g
Initial burette reading (cm3) 20cm3 32.6 cm3 37.5 cm3
Final burette reading (cm3) 32.6cm3 47.5 cm3 47.8 cm3
Volume of NaOH added (cm3) 0.0126L 0.0149 L 0.0103 L
Amount of NaOH added (mol) 0.00126 mol 0.00149 mol 0.00103 mol
Amount of aspirin reacted (mol) 0.00126 mol 0.00149 mo; 0.00103 mol
Mass of aspirin reacted (g) 0.2268 g 0.2682 g 0.1854g
Aspirin in powder (% w/w) 75.6% 86.5% 63.9%
Calculation format experiment
Mass of tube + asprin – mass of tube = mass of asprin per g
2.76 g – 2.46 g + 0.3g
Final burette reading – initial burette reading = volume of NaOH added
32.6 cm3 – 20 cm3 = 12.6 cm3
Volume of NaOH x 0.1 mol = amount of NaOH added
e.g
0.0120 L x 0.1 mol = 0.00126 mol
Amount of asprin = 0.00126 mol
Carbon = 9 x 12
Hydrogen = 8 x 1 180
Oxygen = 4 x 16
180 x 0.00126 = 0.23 mass of reaction
Aspirin powder
0.2268g / 0.3 (mass of asprin) = 0.756
0.756 x 100 =75.6