Acct505 Case Study 2 Springfield

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Acct505 Case Study 2 Springfield
Case Study 2
Springfield Express
Instructions:
Springfield Express is a luxury passenger carrier in Texas. All seats are first class, and the following data are available: Number of seats per passenger train car | 90 | Average load factor (percentage of seats filled) | 70% | Average full passenger fare | \$160 | Average variable cost per passenger | \$70 | Fixed operating cost per month | \$3,150,000 |

a. What is the break-even point in passengers and revenues per month?
Break-even Point
Unit CM= \$160 average full passenger fare – \$70 average variable cost per passenger =\$ 90
Unit Sales= \$3,150,000 Fixed expenses/ \$90 Contribution Margin = 35,000 passengers
Unit Sales= 35,000 passengers * \$160 average full passenger fare= \$5,600,000 in total revenue per month b. What is the break-even point in number of passenger train cars per month?
Number of seats 90*70% average load factor= 63 passengers per train
Unit Sales= 35,000 passengers / 63 pass per train= 555.56 or 556 total passenger train cars per month

c. If Springfield Express raises its average passenger fare to \$ 190, it is estimated that the average load factor will decrease to 60 percent. What will be the monthly break-even point in number of passenger cars?
Number of seats per train = 90 x Load factor percentage = 60%= 54 Pass per train
Unit CM= \$190 Increase pass fare - \$70 average passenger fare= \$120 Unit CM
Unit Sales = \$3,150,000 Fixed Expenses / \$120 Unit CM= 26,250 break even passengers
Unit Sales= 26,250 passengers/ 54 pass per train = 486.11 or 486 monthly break-even point in passenger cars d. (Refer to original data.) Fuel cost is a significant variable cost to any railway. If crude oil increases by \$ 20 per barrel, it is estimated that variable cost per passenger will rise to \$ 90. What will be the new break-even point in passengers and in number of passenger train cars?
Unit CM = 160 average full pass fare- 90 Number of seats= 70
Unit Sales=

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