700000106 CBSE IX Mathematics solutions sample papers 2 20150113155146 1

CBSE IX | MATHEMATICS
Sample Paper – 1 Solution

CBSE
Class IX Mathematics
Term II
Sample Paper - 1 Solution
(SECTION – A)
1. Correct Answer: C
Graph of equation x = k is parallel to the y-axis.
2. Correct Answer: B
As this data will be available through some agency only and will not be collected by the student himself, it is known as secondary data.
3. Correct Answer: A
The positive solutions of the equation ax + by + c = 0 always lie in the 1 st quadrant.
4. Correct Answer: C
Perpendicular from the centre of a circle to a chord bisects the chord.
Given, PR = 5 cm and OR = 12 cm
PO 

12  5
2

2

 PO  144  25
 PO  169
 PO  13
PO = radius = 13 cm
∴ Diameter = 26 cm

5. Correct Answer: D
As the cylinder is dripped vertically to half its height, therefore half the total surface area of the cylinder would be painted.

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CBSE IX | MATHEMATICS
Sample Paper – 1 Solution

6. Correct Answer: A
Let a be the lower limit of the class.
Hence a + 8 is the upper limit of the class.
Also,
Upper limit  lower limit
 Class  mark
2
a  a  8

 10
2
 a   a  8   20
 2a  20  8
 2a  12
a 6
The lower limit of the class is 6.

7. Correct Answer: A

Diagonal of a cuboid = l2  b2  h2  11
 l2  b2  h2  121
Given,
l + b + h = 19

l + b + h

2

 361

 l2  b2  h2  2(lb  bh  lh)  361
 121  2(lb  bh  lh)  361
 2(lb  bh  lh)  361  121  240
Hence, the surface area of the cuboid is 240 cm2 .
8. Correct Answer: C
If the adjacent sides of a quadrilateral are equal, then the quadrilateral is a kite.

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CBSE IX | MATHEMATICS
Sample Paper – 1 Solution

(SECTION – B)
9. In parallelogram ABCD, CD = AB = 16 cm
[Opposite sides of a parallelogram are equal]
We know that,
Area of parallelogram = Base × corresponding altitude
Area of parallelogram ABCD = CD × AE = AD × CF
16 cm × 8 cm = AD × 10 cm
Thus, the length of AD is 12.8 cm.
10.
i.

ii.

Mean is appropriate measure of central tendency in all the