Question for Statistic
For the above sample, compute the following measures. a. b. c. The mean = ∑X/n = 860/10 = 86 The median = (85+86)/2 = 85.5 The variance = ∑ X  X 2/ n1 = {(8486)2 + (8786)2 + (8486)2 + (8886)2 + (8586)2 + (9086)2 + (9186)2 + (83The standard deviation = √8.89 = 2.98 The coefficient of variation = 2.98/86 * 100% = 3.47%
86)2 + (8286)2 + (8686)2 } / (10 1) = 8.89 d. f.
2. In 2008, the average age of students at GUST was 22 with a standard deviation of 3.96. In 2009, the average age was 24 with a standard deviation of 4.08. In which year do the ages show a more dispersed distribution? Show your complete work and support your answer. CV2008 = 3.96/22 * 100% = 18% CV2009 = 4.08/24 * 100% = 17% So, 2008 shows more dispersed distribution 3. A local university administers a comprehensive examination to the recipients of a B.S. degree in Business Administration. A sample of examinations are selected at random and scored. The results are shown below. Grade For the above data, determine a. The mean = ∑X/n = 664/8 = 83 b. c. The median = (85+87)/2 = 86 The standard deviation = √variance ariance = ∑ X  X 2/ n1 = {(9383)2 + (6583)2 + (8083)2 + (9783)2 + (8583)2 + (8783)2 + (9783)2 + (60  83)2 } / (8 1) = 196.29 S0, standard deviation = √196.29 = 14.01 d. The coefficient of variation = 14.01/83 * 100% = 16.88% 93 65 80 97 85 87 97 60
4. The following data represent the daily supply (y in thousands of units) and the unit price (x in dollars) for a product. Daily Supply (y) Unit Price (x) 5 2 7 4 9 8 12 5 10 7 13 8 16 16 16 6
1
a.
e an in er re = 11 X = 7
e a
e c variance
r
ea
ve a a. = ∑

X  X / n1
(y) 5 7 9 12 10 13 16 16
(x) 2 4 8 5 7 8 16 6
6 4 2 1 1 2 5 5
XX 5 3 1 2 0 1 9 1

XX 30 12 2 2 0 2 45 5 80...
Please join StudyMode to read the full document