# Material Science Tutorial

Topics: Atom, Noble gas, Atomic number Pages: 3 (401 words) Published: March 13, 2013
STATIC & DYNAMIC

NAME: AMIRUL AMIN BIN ALIASGAR
ID NO: 50213113002

TUTORIAL 1
QUESTION 1
Calculate the number of neutrons for the following atoms:
a) Aluminum
b) Boron
c) Magnesium
d) Zinc
e) Ferum
f) Argon
Mass Number = (Number of Protons) + (Number of Neutrons)
a) 26.98 = 13 + Neutrons
26.98 – 13 = Neutrons
Neutrons = 13.98

b) 10.81 = 5 + Neutrons
10.81 – 5 = Neutrons
Neutrons = 5.81

c) 24.31 = 12 + Neutrons
24.31 – 12 = Neutrons
Neutrons = 12.31

d) 65.38 = 30 + Neutrons
65.38 – 30 = Neutrons
Neutrons = 35.38

e) 55.85 = 26 + Neutrons
55.85 – 26 = Neutrons
Neutrons = 29.85

f) 39.95 = 18 + Neutrons
39.95 – 18 = Neutrons
Neutrons = 21.95

QUESTION 2
Using the abbreviated quantum number notation (s,p,d,f) write the electronic configuration of the following elements. a) Silicon
b) Germanium
c) Silver
d) Sodium
e) Calcium
f) Molybdenum
a) Full configuration: 1s2 2s2 2p6 3s2 3p2
Noble Gas form: Ne 3s2 3p2

b) Full configuration: 1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p2
Noble Gas form: Ar 3d10 4s2 4p2

c) Full configuration: 1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p6 5s1 4d10 Noble Gas form: Kr 4d10 5s1

d) Full configuration: 1s2 2s2 2p6 3s1
Noble Gas form: Ne 3s1

e) Full configuration: 1s2 2s2 2p6 3s2 3p6 4s2
Noble Gas form: Ar 4s2

f) Full configuration: 1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p6 5s2 4d1 Noble Gas form: Kr 4d5 5s1

QUESTION 3
Compare the relative differences in strength that results from ionic, covalent and metallic boding. There are two types of bond, the strong bonds and the weak bonds. Covalent bond is part of strong bond and it has the highest strength among the strong bond. Ionic bond is part of the strong bond but the strength of ionic bond is a medium strong bond. The metallic bond is also part of the strong bond but the strength of the metallic bond is the weakest among the strong bond.

QUESTION 4...