mass of the sphere holder. (ignore unit of m) B1 Correct calculation of density with unit and in the range 2.2 to 2.8 g / cm3 (ignore s.f.) B1B1B1
[1]
[3]
[Total: 5] 2 (a) y ≥ 60.0 cm (allow values to the nearest cm) and less than the height of the bench with unit. (b) Set square between...
/resistance = weight or no resultant (force) or forces in equilibrium (c) upwards *Apply unit penalty once only
2
(a)
54 N *Unit penalty applies
B1
(b) (i) (the point where) proportionality between force/weight and extension/Hooke’s Law stops (ii) 35 – 20 or 15 (cm) or 25 – 20 or 5...
least 10 cycles OR count no. of cycles in at least 10 s
divide time by number of cycles
C1
A1
(b) (i) decreases OR acceleration slows (down) NOT ‘it slows down’
C1
A1
(iii) 1
B12
4
[4]
C1
(ii) equal to forward / downward force / force down slope OR
constant...
heights (c) idea of resultant force becomes zero (d) decreasing/slowing down, ignore deceleration (e) F = ma in any form, letters, words, numbers (a =) 3.6 (m/s2) c.a.o. (F =) 216 N / 220 N NOT accelerating NOT decelerating NOT accelerating
B1B1B1B1 C1 C1 A1 [Total: 9]
2
(a) mgh OR 0.15 × 10...
, memory for a0c0, a1c0, a2c0 and a3c0 are required - Each chunk of AC has 10*1000 number of memory units
How many chunks of memory we need to compute the cuboid AB: - Try to compute a0b0: Aggregate chunks 1, 17, 33, and 49 - Similarly to compute a1b0: Aggregate chunks 2, 18, 34, and 50 - Similarly...
scale a vector. Vector algebra using coordinates For the vectors A = a1 i + a2 j and B = b1 i + b2 j we have the following algebraic rules. The ﬁgures below connect these rules to the geometric viewpoint. � Magnitude: |A| = a2 + a2 (this is just the Pythagorean theorem) 1 2 Addition: A + B = (a1...
numerical version of the problem stated
in the introduction and the mathematical formulation of the same
in the next section, as below in Table 2.
Table 2
Depot
UnitB1
B2
B3
B4
Stock
A1
c 11 =2
c 12 =3
c 13 =5
c 14 =1
a 1 =8
A2
c 21 =7
c 22 =3
c 23...
the introduction and the mathematical formulation of the same in the next section, as below in Table 2. Table 2 Depot Unit A1 A2 A3 Requirement B1 c 11 =2 c 21 =7 c 31 =4 b 1 =6 B2 c 12 =3 c 22 =3 c 32 =1 b 2 =8 B3 c 13 =5 c 23 =4 c 33 =7 b 3 =9 B4 c 14 =1 c 24 =6 c 34 =2 b 4 =15 Stock a 1 =8 a 2=10 a...
9702
Paper 2 B2
1
(a) (i) all positions (accept 20, 40, 60, 80) marked to within ±5° positions are 40°, 70°, 90° and 102° (-1 for each error or omission) (ii) allow 107° → 113° (b) e.g. more sensitive at low volumes (do not allow reference to ‘accuracy’)
B1B1
[3] [1]
2
(a...
generator
To obtain the two outputs b1 and b2 from the PRBS generator, connect a 5-Volts fixed DC supply to the ‘+ve’ & ‘-ve‘ inputs of the PRBS unit for its biasing, and connect the previously adjusted TTL clock (from any pulse generator) to the clock input of the PRBS unit. Connect the outputs b1...
estimated coefficient b1 does not actually follow the t distribution, consequently t-test would be invalid.
Dickey and Fuller developed a regression based unit root test based on a transformed version of the AR model Xt = b0 + b1 * Xt -1 + εt. Subtracting xt-1 from both sides of the AR model...
) Residual Df= n-k-1=100-2-1 Residual Df=97
D) Regression F= MSR/MSE= .984152/.000118= 8340.27
E) t-Stat of X2 = Coefficient X2/Standard Error of X2= -.0396/.0028797= -13.75
3.)
A) B1= On average a dogs ranking according to urban inhabitants will go up by 1.98 units for every additional...
0.983
2
MODEL 1
Population Regression Model MCi = β1 + β2Qi + εi εi ~ nid[0, 2 ] i = 1, 2, ……, n
Sample Regression Equation MCi = b1 + b2Qi + ei where b1 = sample estimate of β1 b2 = sample estimate of β2 ei = sample estimate of εi, i = 1, 2, ……, n
Estimated Equation
MC = b1 + b2Q...
Ratio and Proportion
• If 2 numbers are in ratio a: b then consider them as ax and bx (where x is the proportionality constant) and apply ax and bx in the given condition of the problem to proceed for answer
• Ratio can be applied between 2units if and only if the same physical quantity is...
budget constraint is B1. It starts at 16 on the Y axis and hits the grapes axis at 16/3, passing through Y = 10, G = 2, last year's bundle. Since last year's indifference curve (ICo) was tangent to B0 at Y = 10, G = 2, and since this year's budget constraint is steeper than last year's, we know...
16 Σ4 15 C4 14 C0 13 GND 12 B1 11 A1 10 Σ1 9
NOTE: The Flatpak version has the same pinouts (Connection Diagram) as the Dual In-Line Package.
4-BIT BINARY FULL ADDER WITH FAST CARRY
LOW POWER SCHOTTKY
J SUFFIX CERAMIC CASE 620-09
16 1
1 A4
2 Σ3
3 A3
4 B3
5 VCC
6 Σ2
7...