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Chapter 7: 7.11
Suppose that we will randomly select a sample of 64 measurements from a population having a mean equal to 20 and a standard deviation equal to 4. A. Describe the shape of the sampling distribution of the sample mean x. Do we need to make any assumptions about the shape of the population? Why or why not? -------------------------------------------------

This would be a normally distributed bell shaped curve. We do not need to make any assumptions because the sample size is at least 30. B. Find the mean and the standard deviation of the sampling distribution of the sample mean x. a. µx=µ +ox=σx=σn µ=20 464=48=.5= σ=.5

C. Calculate the probability that we will obtain a sample mean greater than 21; that is, calculate Px>21. Hint: Find the z value corresponding to 21 by using µx, and σx because we wish to calculate a probability about x. Then sketch the sampling distribution and the probability. a. Px>21 if µ=20) P(z>21-20.5=2 P(z>21)=P(z>)=.0228 A sample distribution normal curve with μx = 20 and σx = .5| | | | | | | | | |

D. Calculate the probability that we will obtain a sample mean less than 19.385; that is, calculate Px<19.385. b. Px<19.385 if µ=20=Pz<19.385-20.5Pz<-1.23=.1093 -------------------------------------------------

Chapter 7: 7.30
On February 8, 2002, the Gallup Organization released the results of a poll concerning American attitudes toward the 19th Winter Olympic Games in Salt Lake City, Utah. The poll results were based on telephone interviews with a randomly selected national sample of 1,011...

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BUS308 STATISTICS FOR AMANAGERS
BUS308 Week 1 DQ 1 Language
Numbers and measurements are the language of business.. Organizations look at results, expenses, quality levels, efficiencies, time, costs, etc. What measures does your department keep track of ? How are the measures collected, and how are they summarized/described? How are they used in making decisions? (Note: If you do not have a job where measures are available to you, ask someone you know for some examples or conduct outside research on an interest of yours.)
BUS308 Week 1 DQ 2 Levels
Managers and professionals often pay more attention to the levels of their measures (means, sums, etc.) than to the variation in the data (the dispersion or the probability patterns/distributions that describe the data). For the measures you identified in Discussion 1, why must dispersion be considered to truly understand what the data is telling us about what we measure/track? How can we make decisions about outcomes and results if we do not understand the consistency (variation) of the data? Does looking at the variation in the data give us a different understanding of results?
BUS308 Week 1 Problem Set Week One
Problem Set Week One. All statistical calculations will use the Employee Salary Data set (in Appendix section).
Using the Excel Analysis ToolPak function Descriptive...

...the chance that an uncertain event will occur.
5. Question : The price-to-earning ratio for firms in a given industry is distributed according to normal distribution. In this industry, a firm with a Z value equal to 1
6. Question : The expected value of a discrete random variable is:
7. Question : For a continuous distribution, P(a ≤ X ≤ b) = P(a <X< b).
8. Question : The following formula: P(A U B) = P(A) + P(B) - P(A ∩ B) represents
9. Question : The MPG (mileage per gallon) for a mid-size car is normally distributed with a mean of 32 and a standard deviation of .8. What is the probability that the MPG for a selected mid-size car would be less than 33.2?
10.Question : The height of a continuous probability curve over a given point is
BUS308 Week 2 Quiz
1. The one-sample t-test differs from the z-test in which way?
2. The z-test can be used to test mean differences even when the initial data set is not normally distributed.
3. What question does the z test answer?
4. Type I errors may occur with ______ results and type II errors with ______ results.
5. Which of the following defines statistical significance?
6. How do statistical tests like the one sample t adjust for the absence of parameter values?
7. Why do the critical values change with degrees of freedom for the t-tests?
8. Each different t-distribution is defined by which of the following?
9. The critical value of t to determine statistical significance depends on the sample size.
10....

...Running head: WEEK 4 ASSIGNMENT 1
Week 4 Assignment
Sarah Doppelmayr
Statistics for Managers
BUS308
Edward Kaplan
January 28, 2013
WEEK 4 ASSIGNMENT 2
Week 4 Assignment
Chapter 9: 9.13 Recall that “very satisfied” customers give the XYZ-Box video game system a rating that is at least 42. Suppose that the manufacturer of the XYZ-Box wishes to use the random sample of 65 satisfaction ratings to provide evidence supporting the claim that the mean composite satisfaction rating for the XYZ-Box exceeds 42. A. Letting mew represent the mean composite satisfaction rating for the XYZ-Box, set up the null hypothesis H0 and the alternative hypothesis Ha needed if we wish to attempt to provide evidence supporting the claim that mew exceeds 42. H0: mu 42 B. The random sample of 65 satisfaction ratings yields a sample mean of x bar = 42.954. Assuming that sigma equals 2.64, use critical values to test H0 versus Ha at each of .10, .05, .01 and .001. z-statistic: z = (xbar - μ)/(σ/√n) z = (42.954 - 42 )/(2.64/√65) z = 0.954 / (2.64/8.0623) z = 2.9134 alpha z-crit result 0.10 1.282 significant 0.05 1.645 significant
WEEK 4 ASSIGNMENT 3
0.01 2.326 significant 0.001 3.09 not significant C. Using the information in part b, calculate the p-value and use it to test H0 versus Ha at each of .10, .05, .01 and .001. The p-value is 0.0025. This being stated, the result is significant at 0.10, 0.05, and 0.01, because p...

...Week 4 AssignmentBUS308 Statistics for Managers
January 28, 2013
9.13) Recall that “very satisfied” customers give XYZ-Box video game system a ratting at least 42. Suppose that the manufacturer of XYZ-Box wishes to use the random sample of 65 satisfaction ratings to provide evidence supporting the claim that the mean composite satisfaction rating for the XYZ-Box exceeds 42.
a. Letting u represent the mean composite satisfaction rating for the XYZ-Box, set up the null hypothesis H0 and the alternative hypothesis Ha needed if we wish to attempt to provide evidence supporting the claim that µ exceeds 42.
H0: mu 42
b. The random sample of 65 satisfaction rating yields a sample mean of x = 42.954. Assuming that s equals 2.64, use critical values to test H0 versus Ha at each of a = .10, .05, .01, and .001.
z-statistic:
z = (xbar - µ)/(σ/√n)
z = (42.954 - 42 )/(2.64/√65)
z = 0.954 / (2.64/8.0623)
z = 2.9134
alpha z-crit result
0.10 1.282 significant
0.05 1.645 significant
0.01 2.326 significant
0.001 3.09 not significant
c. Using the information in part b, calculate the p-value and use it to test H0 versus Ha at each of a = .10, .05, .01, and .001.
Upper tail p- value for z = 2.9134 is 00018
Since 0.0018 < 0.10, 0.05 and 0.01, we reject Ho and accpt Ha at a = 0.10,
0.05 and 0.01, and conclude that the mean rating exceeds 42
Since 0.0018 > 0.001, we fail to reject Ho at a = 0.001, and fail to...

...BUS308 Week 4 assignment_ 9.13_9.22_and 12.10_12.18(a)
9.13 Recall that “very satisfied” customers gave the XYZ-Box video game system a rating that is at least 42. Suppose that the manufacturer of the XYZ-Box wishes to use the random sample of 65 satisfaction ratings to provide evidence supporting the claim that the mean composite satisfaction rating for the XYZ-Box exceeds 42.
a. Letting represent the mean composite satisfaction rating for the XYZ-Box, set up the null hypothesis and the alternative hypothesis needed if we wish to attempt to provide evidence supporting the claim that exceeds 42.
b. The random sample of 65 satisfaction ratings yields a sample mean of x = 42.954. Assuming that equals to 2.65, use critical values to test versus at each of a = .10, .05, .01, and .001.
z = [ (42.954 – 42) / (2.64 / 65 ] = 2.91
Reject Points
Since 1.28<1.645<2.33<2.91<3.09, reject with =.10, .05, .01, but not with .001.
c. Using the information in part b, calculate the p-value and use it to test versus At each of a = .10, .05, .01, and .001
p-value
Since p-value = .0018 is less than .10, .05, and .01, reject at those levels of , but not with it ( =.001).
d. How much evidence is there that the mean composite satisfaction rating exceeds 42?
There is a lot of evidence that the mean composite satisfaction rating exceeds 42.
9.22 How do we decide whether to use...

...Assignment 1: HRM in an MNE
Nicole Boehm (Coveley)
Global Human Resource Management (Bus 325)
Professor Sandy Hughes
July 24, 2014
1. Compare and contrast two (2) main differences between domestic and international HRM.
Human resource management refers to all activities undertaken by an organization to effectively utilize human resources. The activities included for HRM is planning, performance management, staffing, development, compensation, and employee relations. Over the past couple of years organizations have been identifying the link of HRM with organizational strategy in order to develop a strategic approach to HRM and to also offer an understanding of how single country or domestic human resource management practices can contribute to organizational performance by leveraging people's capabilities (e.g. Schuler, et al., 1993). In order to understand which activities change when HRM goes international, we have to define IHRM first. Broadly speaking, the consensus is that IHRM is about the worldwide management of human resources (Brewster, 2002). In other words, the purpose of IHRM is to enable the multinational enterprise (MNE) to be successful on a global level. Strategic international human resource management (SIHRM) focuses on strategic HRM in MNEs and recognizes the importance of linking HRM with organizational strategies in order to achieve sustainable competitive advantage (Schuler & Tarique, 2007: 718).
2. Examine...

...
“Analysis of Direct Cost”
Katherine Morales
Professor Bartorillo
May 31, 2015
BUS 315
To VectorCal, developing drones is mere child’s play and nothing more than a remote controlled aircraft type device to fly around outdoors. VectorCal has utilized this as a business venture, in that the camera can be mounted so that the drone can now take aerial photos or provide live video of what is happening on the ground from an aerial perspective. However, instead of leaving the drones play like in size, they increased the scale and added a sophisticated navigation system. They have also added small weapons systems and created and entirely different beast. Now the drones are capable of going longer distances providing aerial photography that will provide the enemy location on which they can then develop their strategy of attack and then take that same information to lead the attack without ever leaving their office. There are many resources that are involved and with those resources comes the cost related to them.
There are many cost that are associated with the production of this system as it takes precise engineering, precise manufacturing to the exact specifications, machinery, labor, and the ability to handle the necessary preciseness of manufacturing these systems. There are also costs associated with testing and further developing on the flawed components found by the testing, and the list goes on. For example, the two main costs associated with production...

...Subject Code: ECOM90009
Subject Name: Quantitative Methods for Business
Assignment Number: 2
Workshop Day and Time: Thursday 02:15pm
Tutor Name: Jackson Yuen
Student ID Number
Student Name
1.
2.
3.
4.
Question 1:
a.
Count
150
Mode
22
Sum
3231
Standard Deviation
4.728
Range
29
Sample Variance
22.357
Maximum
36
Coefficient of Variance
0.22
Minimum
7
Mad
3.0
Mean
21.54
25th percentile
18.5
Median
22
75th percentile
25
The central location of the distribution includes mean, median and mode. As illustrated above, the mean number, median number and mode number of the distribution of installation times are 21.54,22 and 22. There are little differences among the three numbers which means that the shape of the distribution is nearly symmetric.
The variance of the installation time of this sample is 22.357 while the standard deviation is 4.728. The installation time ranges from 7 minutes to 36 minutes. The coefficient of variance is 0.22 which is low. The mad of the sample is 3.0.
The first quartile is 18.5 indicating that 25% of the purchasers’ installation time is less than 18.5 minutes. However the third quartile is 25 which shows that 75% of the purchasers spent less than 25 minutes to install the software.
b.
Yes, we are able to estimate the mean installation time using this data. We do not know the variance of the population so we need to standardise the mean of...