In this table, the numbers in the gender, denomination, and church attendance columns represent the following.

Gender
1. Male
2. Female

Denomination
1. Episcopal
2. Lutheran
3. Methodist
4. Presbyterian
5. Other mainline Protestant
6. Baptist
7. Other Evangelical Protestant
8. Pentecostal
9. Charismatic
10. Non-denominational
11. Catholic
12. Other

Church Attendance
1. less than once a month
2. once a month
3. a few times a month
4. once a week
5. twice a week
6. three or more times a week

a. What is the mean age of this sample? What is the standard deviation? The mean age is 47.5 years old. The standard deviation is 10.74832 years. http://easycalculation.com/statistics/standard-deviation.php

b. Create a frequency distribution table for denomination. |Denomination |Frequency |
|1 |1 |
|2 |2 |
|3 |0 |
|4 |2 |
|5 |1 |
|6 |3 |
|7 |3 |
|8 |1 |
|9 |3 |
|10 |3 |
|11 |0 |
|12 |1 |

c. What is the percentage of people who identify themselves as Baptist in this sample? The percentage of Baptists is 15%. I found this by dividing the amount of total number of church attendance (20) by the total number of Baptist attendance (5). d. What is the mode of church attendance?

The mode of church attendance is twice a week. I found this by creating a frequency table.

...Question 1
a. Mean age = 960/20=48
b. Standard Deviation = 10.74832
Web address: http://easycalculation.com/statistics/standard-deviation.php
Frequency distribution table for denomination.
Score f(frequency)
11
2 2
4 2
5 1
6 3
7 3
8 1
9 3
10 3
12 1
N=30
c. What is the percentage of people who identify themselves as Baptist?
3/20 = .15 x 100 = 15%
What is the mode of church attendance?
5
Question 2
a. What is the Z score for a car with a price of $33,000?
Z=2.85714286
b. What is the Z score for a car with a price of $30,000?
Z=2
Web address for calculator: http://www.danielsoper.com/statcalc3/calc.aspx?id=22
c. At what percentile rank is a car that sold for $30,000?
97.72%
Webcalculator used: http://easycalculation.com/statistics/zscore-to-percentile.php
3. One student’s Math score was 70 and the same individual’s English score was 84. On which exam did the student do better?
Math: +3 points divided by 9.58 SD = .3132
English: + 6 points divided by 12.45 SD = .482
The student did better on the English test.
4.Suppose you administered an anxiety test to a large sample of people and obtained normally distributed scores with a mean of 45 and standard deviation of 4. Do not use...

...WebCalculatorExercise 5
ANOVAs
1. A researcher is interested in comparing the effectiveness of three different kinds of therapy for anger problems. Eight participants are randomly assigned to three treatment conditions: Cognitive Therapy (CT), Cognitive-Behavioral Therapy (CBT), and Interpersonal Therapy (IT). All participants complete the weekly treatment for 8 weeks. Participants take an anger test before and after the 8-week treatments. Each participant’s difference score (= anger score after the treatment minus (–) anger score before the treatment) is shown in the following table. The three therapists in this experiment have equal educational levels and clinical experiences.
CT | CBT | IT |
3 | 5 | 7 |
4 | 4 | 8 |
4 | 6 | 9 |
4 | 6 | 10 |
3 | 5 | 6 |
8 | 4 | 7 |
6 | 9 | 11 |
2 | 7 | 10 |
| | |
a. What statistical test should be used to analyze the data?
The between subjects one-way randomized ANOVA should be used to analyze the data. Although the total number of participants is not indicated it would not make sense to have each participant in the three different therapies either concurrently or consecutively. The data are on an interval/ratio scale. The following assumptions are met:
● The underlying distribution is normally distributed.
● The variances among the populations being compared are
homogeneous.
● The observations are all independent of one another.
b. Identify H0 and...

...99% measure confidence range, 2.576σ
19.812335712736 - 75.187664287264
The 99.9% measure confidence range, 3.291σ
12.12728914232 - 82.87271085768
The 99.99% measure confidence range, 3.891σ
5.6782990132987 - 89.321700986701
The 99.999% measure confidence range, 4.417σ
0.024684333523602 - 94.975315666476
The 99.9999% measure confidence range, 4.892σ
-5.0807661852847 - 100.08076618528
B. Create a frequency distribution table for denomination.
Denomination Frequency11
2
2
3
0
4
2
5
1
6
3
7
3
8
1
9
3
10
3
11
0
12
1
C. What is the percentage of people who identify themselves as Baptist in this sample?
The percentage of Baptists is 15%. I found this by dividing the amount of total number of church attendance (20) by the total number of Baptist attendance (5).
d. What is the mode of church attendance?
The mode of church attendance is twice a week. I found this by creating a frequency table. 3/20 = .15 x 100 = 15%
Attendance
Frequency
1
0
2
2
3
3
4
2
5
8
6
5
2. The results of a recent survey indicate that the average new car costs $23,000, with a standard deviation of $3,500. The price of cars is normally distributed.
A. What is a Z score for a car with a price of $ 33,000?
The Z score for a car with a price of $33,000 is 2.8571.
http://easycalculation.com/statistics/z-score-standard.php
B....

...IP addressing Scenario
With a newly founded company that has approximately 145 hosts that must be connected to a network or networks you would want to consider some things that will benefit the company and the users of the hosts. Since this is to be commercial type business the subnet ranges that should be used are 1.0.0.0 to 126.0.0.0, where the numbers in the second through fourth octet would be 0 to 255.
This is the kind of company that should have their addresses assigned dynamically only because there are 145 hosts which range from computers to printers and it would be easier if each time the user is to log on they could just have a new address assigned to them. This would help make things easier when trying to connect one printer to a computer that is on the network. When looking at the overall number of hosts that this one company has it would be a lot easier if 2 networks were made for this one company. It would be hard having 145 hosts connected to one network.
If two networks were created then overall number of hosts can be divided to make it easier when trying to connect things like scanners or printers to specific computers. With the two networks it would make the network work more effectively and the overall speed of the network would stay at a constant processing rate. Then with having two networks it would help decrease any security issues.
The main accommodation that I saw necessary for this kind of company was security. Since there are 145 hosts and...

...Exercise1
Cell Transport Mechanisms and Permeability
Name ____________________________________________________________
Lab Time/Date ______________________________
Activity 1 Simulating Dialysis (Simple Diffusion)
1. Describe two variables that affect the rate of diffusion.
* The size of the pores of the membrane
* The size of the molecule diffusing through the membrane
2. Why do you think the urea was not able to diffuse through the 20 MWCO membrane? How well did the results compare with your prediction?
* Because the pores of the membrane were not large enough
* I predicted this correctly.
3. Describe the results of the attempts to diffuse glucose and albumin through the 200 MWCO membrane. How well did the results compare with your prediction?
I predicted that only glucose would diffuse through it and was right. Albumin is too heavy to diffuse through that membrane.
4. Put the following in order from smallest to largest molecular weight: glucose, sodium chloride, albumin, and urea.
NaCl, Urea, Glucose, Albumin
Activity 2 Simulated Facilitated Diffusion
1. Explain one way in which facilitated diffusion is the same as simple diffusion and one way in which it differs.
-Similar – They pass through the membrane without the use of ATP, they’re both forms of passive transport.
-Different - The solutes in facilitated diffusion pass through a carrier...

...Exercise1
XXXXX
XACC/290
August XX, 2014
XXXXXX
E3-4
Describe each transaction.
1. The company issued shares of stock to stockholders’ equity increased for the month.
2. The company purchased equipment for $1,000 cash and $4,000 on account.
3. The company purchased supplies for $750 cash.
4. The company receives $4,100 in cash revenue and $5,400 in accounts receivable.
5. The company paid $1,500 cash for accounts payable.
6. The company paid a $2,000 dividend.
7. The company paid $800 cash for rent.
8. The company received a payment for accounts receivable.
9. The company paid its employees’ salaries in the amount of $3,000.
10. The company paid their utility expense on account.
Determine how much the stockholders’ equity increased.
The stockholders’ equity increased by $3,600.
Compute the net income for the month.
The net income for the month is $25,600.
E3-9
Journalize
Date ____ Account Title ____ Debit Credit_______________
May 4 Supplies $700
Accounts Payable $700
7 Accounts Receivable $6,800
Service Revenue $6,800
8 Accounts Payable $850
Supplies $850
9 Cash $1,000
Equipment $1,000
17 Salary $530
Expense $530
29 Cash $1200
Prepaid Insurance $1200
3-5A
Journalize...

...Exercise1:
Dissolved oxygen is oxygen that is trapped in a fluid, such as water. Since virtually every living organism requires oxygen to survive, it is a necessary component of water systems such as streams, lakes and rivers in order to support aquatic life. The dissolved oxygen is measure in units of ppm—or parts per million. Examine the data in Table 2 showing the amount of dissolved oxygen present and the number of fish observed in the body of water the sample was taken from; finally, answer the questions below.
Table 2: Water quality vs. fish population
￼￼
1. Based on the information in Table 2, what patterns do you observe?
The more dissolved oxygen in the water, the more fish are observed in that area of water.
2. Develop a hypothesis relating to the amount of dissolved oxygen measured in the water sample and the number of fish observed in the body of water.
If there is more dissolved oxygen in the water, there will be more fish are observed in the area of water.
3. What would your experimental approach be to test this hypothesis?
To test the hypothesis I would do the same to get the results on the table. Test the oxygen in different areas of the water and keep track of the amount of fish in the area to later compare the results.
4. What are the independent and dependent variables?
Independent Variable- Dissolved Oxygen
Dependent- Fish
5. What would be your control?
In this experiment I...