1. Economic periods of prosperity followed by recession are described as: A. Secular trend B. Seasonal variation C. Cyclical variation D. Erratic variation 2. The following linear trend equation was developed for annual sales from 1995 to 2001 with 1995 the base or zero year. = 500 + 60t (in $thousands). What are the estimated sales for 2005 (in $thousands)? A. $500 B. $560 C. $1,040 D. $1,100 3. Which one of the following is not a component of a time series? A. Secular trend B. Moving average C. Seasonal variation D. Irregular variation E. All of the above are components 4. The possible values for the Durbin-Watson statistic are A. any value B. any value greater than zero C. any value from 0 to 4 inclusive D. any value less than zero. 5. A question has these possible choices—excellent, very good, good, fair and unsatisfactory. How many degrees of freedom are there using the goodness-of-fit test to the sample results? A. 0 B. 2 C. 4 D. 5

6. What is the critical value at the 0.05 level of significance for a goodness-of-fit test if there are six categories? A. 3.841 B. 5.991 C. 7.815 D. 11.070 7. What is our decision regarding the differences between the observed and expected frequencies if the critical value of chi-square is 9.488 and the computed value is 6.079? A. The difference is probably due to sampling error; do not reject the null hypothesis B. Not due to chance; reject the null hypothesis C. Not due to chance; do not reject the alternate hypothesis D. Too close; reserve judgment 8. The chi-square distribution is A. positively skewed. B. negatively skewed. C. normally distributed. D. negatively or positively skewed. 9. Two chi-square distributions were plotted on the same chart. One distribution was for 3 degrees of freedom and the other was for 12 degrees of freedom. Which distribution would tend to approach a normal distribution? A. 3 degrees B. 12 degrees C. 15 degrees D. All would 10. If the...

...indicated to what kind of test was going to be used and since I claimed that the rural area were going to have a lower average number of beds it states that the shaded area on the critical value test will be less than zero.
Table 1. Descriptive statistics for the given null and alternative hypothesis that includes the sample, mean, median, standard deviation, maximum values, and minimum values.
Sample Size
Mean
Median
Standard Deviation
Maximum Value
Minimum Value
Rural Area...

...916441174
Range 3.5
Minimum 1.5
Maximum 5
Sum 206
Count 49
Confidence Level(95.0%) 0.196039006
In both the Charismatic and the punitive condition data sets there were 49 people surveyed. We know this because we were able to use descriptive statistics to show the count and that shows the number of people surveyed. The average or the mean of the charismatic condition is 4.20. The standard error is saying that 0.0975 % is the error that will normally occur if two...

...shirt is classiﬁed as either perfect or as ﬂawed and the shift that produced the shirt is also recorded. In the test on the relation between quality and shift that the manager can now perform, what is the number of degrees of freedom of the test statistic? a. The number of degrees of freedom is 2. b. The number of degrees of freedom is 6. c. The number of degrees of freedom is 598. d. The number of degrees of freedom is 599. 3. A police oﬃcer believes that half of the cyclists...

...KEYWORDS: chi-square test of independence
7. Referring to Table 12-1, the calculated test statistic is
a) -0.9991.
b) -0.1368.
c) 48.1849.
d) 72.8063.
ANSWER:
c
TYPE: MC DIFFICULTY: Easy
KEYWORDS: chi-square test of independence, test statistic
8. Referring to Table 12-1, at 5% level of significance, the critical value of the test statistic is
a) 3.8415.
b) 5.9914....

...Case 1:
1)
Hypotheses:
H₀: μ=94.4
H₁: μ>94.4
Rejection Region:
Degree of freedom:
d.f=n-1
=49
t> ta,d.f
t>0.05,49
t>1.6766
Test statistics:
t=
From using the Data Analysis Plus in Excel we get:
t-Test: Mean
Cleanser Spending
Mean
102.4000
Standard Deviation
27.5711
Hypothesized Mean
94.4
df
49.0000
t Stat
2.0517
P(T1.6766).
2)
± ta/2,d.f s/
From using the Data Analysis Plus in Excel we get:...

...Statistical Data Analyses
Graeme Ferdinand D. Armecin, MHSS
Outline of Presentation
Overview of Research Designs Functions of Statistics Sampling Principles of Analysis and Interpretation (with Computer Package) – Descriptive Statistics – Inferential Statistics
Graeme Ferdinand D. Armecin, MHSS
Statistical Data Analyses
Purposes of Research Design
Exploratory/Descriptive Research design – Basic or fundamental in...

...1 Statistics plays a vital role in almost every facet of human life. Describe the functions of Statistics.Explain the applications of statistics.
Meaning of statistics
Functions of statistics
Applications of statistics.
Ans:Statistics plays an important role in almost every facet of human life. In business context, managers are required to justify decisions on the basis of data. They need statistical models to support...

...How many standard deviations is my hypothesis (sample mean) is away from the actual (null hypothesis population mean)
T – statistic
Rejecting the null may be a mistake = p –value
ONE SAMPLE
3 formulas
T.Dist.rt (t, sample size - 1 “df”) -> alternative that mu is bigger than a
1 – T.Dist.rt (t, sample size – 1) -> mu is less than a
T.Dist.2t(t,samplesize - 1) -> not equal to
p < significant level reject the null
NEVER accept null
TWO SAMPLE...