Abstract
The specific heat capacity of various metals can be calculated and compared to accepted literature values. Dropping heated metal samples into a calorimeter filled with water and then measuring the change in the temperature of the system accomplished this. The metal samples were heated in a boiling water bath and were assumed to be at 100 C when they were removed. It was added to a calorimeter and stirrer with a measured mass of room temperature tap water. The temperature was taken through the lid of calorimeter to mitigate heat loss. These temperatures were recorded and used to calculate the specific heat capacity of the metal samples. The specific heat capacity of the aluminum was found to be 1.44 J/(g*C) and the relative error was found to be 0.54. The specific heat capacity of the copper sample was found to be 0.499 J/(g*C) and the relative error was found to be 0.112. The specific heat capacity of the iron was found to be 0.596 J/(g*C) and the relative error was found to be 0.148. The values found for the copper and the iron were slightly higher than the accepted literature value but still rather close. The value found for the aluminum was much higher than the accepted.

Sample Calculations
-see attached sheet.

Data Analysis

Table of Data collected to measure specific heat capacity.

| |Aluminum |Copper |Iron | |Metal mass, g |21.84 |72.04 |63.21 | |Initial Metal Temp, C |100 |100 |100 | |Initial Temp of System, C |21.5 |21.1 |20.5 | |Final Temp of System, C...

...AIT Physics 1 Honors
Laboratory: SpecificHeat and Conservation of Energy
When energy in the form of heat Q is added to a material, the temperature of the material rises. Note that
temperature, in units of degrees Celsius (°C) or Kelvin (K), is a measure of how hot or cold a substance
is, while heat, in units of joules (J) or calories (cal), is a measure of its thermal energy. 1cal = 4.19J.
A measure of the efficiency with which a substance can store this heat energy is known as specificheatcapacity, or simply the specificheat, . The greater the material's specificheat, the more energy must be
added to change its temperature. As an example, the specificheat of water is given as C
4186
J
,
Kg C
which means that 4186 Joules of heat are necessary to raise one kilogram of water one degree Celcius or
Kelvin. Other common specificheat values for various other materials are listed in CJ6 Chapter 12.
The heat necessary to cause a temperature change in a material (not a phase change) is Q
mC T
where C is the specificheatcapacity of that material. Normally the change in temperature of the substance
is the difference between its final and initial temperatures T T f Ti
When two...

...as a whole, and treating the energy transfer as the flow of heat, rather than kinetic energy transfer among particles.
|SpecificHeat for Various Materials |
|Material |SpecificHeat |
| |(J/kg C°) |
|Water |4186 |
|Aluminum |900 |
|Steel |448 |
|Brass |386 |
|Copper |380 |
Experiments have shown that the heat transfer Q = mcΔT, where ΔT = Tfinal-Tinitial of the object you’re considering, m is its mass, and c is referred to as the “specificheat” of the material it’s made up of. For most materials over a wide range of temperatures, c is close enough to a constant value that we will consider it to be exactly constant. Note that a positive Q means that energy flowed into the object (raising its temperature), while a negative Q means that energy left the object (leaving it at a lower temperature than at the beginning). Also note that you must be careful to associate the mass, specificheat, initial temperature, and final temperature, for the appropriate object being considered in any particular calculation, and not some other...

... January 14, 2013
B.S. Chemistry I Tuesday 1:30- 4:30 Mr. John Waruel Liwag
EXPERIMENT NO: 3
SPECIFICHEAT OF SOLIDS
I.OBJECTIVES
To determine the HeatCapacity of calorimeter, experimentally.
To determine the SpecificHeat of ceratin solid specimen, experimentally.
II. APPARATUS
Calorimeter
Solid samples of Al, Cu, Fe shots
250 ml beaker
Thermometer
Rags
Boiler for hot water
Digital platform balance
III. ABSTRACT
Specificheat measurements are useful not only to determine the thermal properties of solids, but also to study phase transition anomalies (such as changes in magnetic ordering and the onset of superconductivity) in solid materials. The experiment involves directly applying heat to a sample and either looking at the temperature rise or decay (or both!) in order to determine the heatcapacity of the material as a function of temperature. As a sample passes through a phase transition it is necessary to supply the latent heat associated with that change, this leads to a dramatic increase in the heatcapacity of the material.
IV. THEORY
Thermal energy is an internal energy that...

...SpecificHeat Lab
Objective: Find the specificheat of the unknown metal given using calorimetry.
Background Theory:
In every reaction, energy is transferred between a system and its environment. A system encompasses the substances that are involved in a reaction, and everything else in the universe other than the system is called the environment. The standard SI unit of energy is Joules (J). Temperature is the level of excitement of the atoms in a substance. In most cases, energy is transferred by heat. Heat is the energy released from a change in temperature. The standard units for heat and temperature are in degrees Celsius or Kelvin (both have the same increment between each degree, the difference is that Celsius is based off of the freezing point of water, and Kelvin is based off of absolute zero. A calorie is the amount of energy needed to heat one gram of water by one degree Kelvin, or 4.1868 joules. Now scientists more commonly use Joules.
Every substance has a specificheatcapacity. A specificheatcapacity is the amount of energy needed to heat one gram of a substance by one degree Kelvin. Heatcapacity is the amount of energy needed to heat a given sample of any size by one degree Kelvin. You can...

...IB Physics Lab: Finding SpecificHeatCapacity of a Solid using Method of Mixtures | VISHWASHANTI GURUKUL Department of science-Physics Year: 2012-14 Level: HL |
Name of candidate : ……………………………………………… Date: 08/01/2013
Name of Teacher: Chandra Sekhar Mogilisetti
“Professor Lieber notes that using copper in the manufacture of coffee cups is not the wisest choice.”SpecificHeatCapacity of Solid
In this lab you will be assessed on the following criteria:
* Data collection and Processing
* Conclusion and Evaluation
AIMS
1. To determine the specificheatcapacity of a given metallic solid using the method of mixtures.
2. To obtain the values of specificheatcapacities of different materials from other groups and compare them.
3. To postulate which metal among those studied could be used to build a space rocket which should be light, strong and not get heated up much on re-entry.
4. To postulate which metal among those studied could be used to build a cooking vessel which should be heavy, and get heated up quickly.
INTRODUCTION
When substances at different temperatures are brought into contact they experience thermal
interaction....

...Title: SpecificHeatCapacities of Metals
Experiment Date: 3/28/2012
Report Date: 4/4/2012
Purpose:
The purpose of the lab is to measure the specificheatcapacities of aluminum, steel and brass.
Theory:
The amount of heat (ΔQ) required to change the temperature of an object is proportional to the mass (m) of the object and the temperature change (ΔT) of the object. ΔQ= cmΔT where c is called as the specificheatcapacity of the material. In the calorie units system the unit of quantity of heat “calorie” is defined as the amount of heat required to raise the temperature of one gram of water from 14.5°C to 15.5°C. Then, water has a specificheat of 1 cal/g°C, .
The specificheat of a material can be determined experimentally by measuring the temperature change of a given mass of material produced by a quantity of heat. This is done by method of mixture. An object of mass m is heated to an initial temperature T1 and then dropped into water of mass mw at temperature Tw. The mixture will come to equilibrium at a final temperature T2, if no energy is lost to the surroundings during the process, conservation of energy requires that the heat lost by the object equals the heat gained by the water, m c...

...Investigation 11
Specificheatcapacity
Aim:
Investigate to determine the specificheatcapacity of a metal cube provided
Apparatus:
-thermometer
-stirrer
-water
-calorimeter
-beam balance
-metal cube
-beaker
Procedure:
Using the normal equipment for Thermal Physics investigations, you are required to design and carry out an investigation to determine the specificheatcapacity of a metal cube provide by teacher. Furthermore, you will need to compare your obtained value with published values, and confirm your identification of the metal by choosing a second physical property of the metal, and designing and carrying out an investigation to justify your findings.
Raw data:
Water= initial temperature: 24 , volume: 100ml
Final temperature: 28
Metal Block= initial temperature: 100, mass:10g
Final temperature : 28
Mass of calorimeter= 32g , Temperature same as water
Process data:
Cw = 4200J×ng-1°C-1 Cal = 900kg-1°C-1
Cw×Mw(tfw－tiw)+CaMc×(tfw-tiw)= CmMm(100－tfm)
900×32×(28－24)＋4200×100×(28－24)=Cm×10×(100－28)
Cm ＝ 115200 ÷70÷75
Cm ＝ 2194.2 J/kg
Limitation:
The numbers on the calorimeter is not nicety enough which leads the data not accurate. These matter might be get influenced by air temperature.
Conclusion:
As you can see in the raw data, heat from the...

...Aim: To determine the specificheatcapacity of water by heating water and recording temperatures at regular intervals.
Hypothesis: (i) P = Q /t
(ii) Q = m c ΔT
Where,
P is the power of the heater
Q is the total energy provided by the heater
t is the total time for which the heater was used
m is the mass of water
c is the specificheatcapacity of water, and
ΔT is the change in temperature
From (i) and (ii) m cΔT = P t
ΔT = (P/mc) * t
This is in the form y = mx + c, where
y = ΔT
m = (P/mc), and
x = t
Therefore, plotting ΔT in the y-axis with t in the x-axis gives us the slope (P/mc), from which we can find ‘c’.
DATA COLLECTION AND PROCESSING
Volume of water = 400 ± 1 cm3? [measured using a beaker of least count 1 cm3]
Density of water = 1 gcm-3
Therefore, Mass of water = Density x Volume = 400 g = 0.400 kg
%error in mass = % error in volume = 1/400 * 100 = 0.3%
Error in mass = 0.3% of 0.400 kg = 0.001 kg
Mass = 0.400 ± 0.001 kg
Power of heater = 500W
Table 1: Raw data table showing temperatures at intervals of 15 seconds while heating
Time interval/s ± 0.1 s
Temperature/°C
± 0.5°C
i
Ii
Iii
iv
15.0
27.0
28.0
28.0
27.0
30.0
33.0
33.0
34.0
34.0
45.0
38.0
39.0
39.0
39.0
60.0
43.0
44.0
43.0
44.0
75.0
48.0
48.0
48.0
50.0
90.0
51.0
52.0
53.0
54.0
105.0
56.0
58.0
58.0
57.0
120.0
61.0
62.0
62.0...