Solving Exponential and Logarithmic Equations

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  • Topic: Logarithm, Polynomial, Exponentiation
  • Pages : 3 (494 words )
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  • Published : April 12, 2013
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Solving Exponential and Logarithmic Equations
Exponential Equations (variable in exponent position)
1. Isolate the exponential portion ( base exp onent ): Move all non-exponential factors or terms to the other side of the equation. 2. Take ln or log of each side of the equation. • Make sure to use ln if the base is “e”. Then remember that ln e = 1 . • Make sure to use log if the base is 10. • If the base is neither “e” nor “10”, use either ln or log, your choice.. 3. Bring the power (exponent) down into coefficient position. 4. Use various algebra techniques to solve for the variable. 5. Check your answer by evaluating the original equation with your calculator.

Example: 4e 2 x −3 = 40

Answer is on next page

Logarithmic Equations
1. 2. 3. 4. 5. Move all log terms to one side of the equation, all non-log terms to the other side. Combine log terms into a single log term using the laws of logarithms. Write the log equation in its exponential form. (remember: 2 3 = 8 ↔ log 2 8 = 3 ) Use various algebra techniques to solve for the variable. Check your answer using your calculator. Remember that domain problems occur in log functions. • If the base of the log is “10” or “e”, you can use the appropriate calculator keys. • If the log is not “10” or “e”, you may need to use the change of base formula before using your calculator.

Example:

log 5 ( x + 1) − 2 = log 5 ( x − 1)

Answer is on next page

Solving Exponential and Logarithmic Equations: Answers
Exponential Equation: 4e 2 x −3 = 40 Divide both sides by 4 to isolate the exponential portion

e 2 x −3 = 10

Take ln of both sides (use ln because the base is “e”) Use the law of logs that allows you to bring the power into coefficient position Recall that ln e is equivalent to 1, so the equation is actually → Now just solve for x using algebra (add 3 to both sides, then divide both sides by 2)

ln e 2 x −3 = ln 10 (2 x − 3) ln e = ln 10
2 x − 3 = ln 10

2 x = 3 + ln 10
x=

3 + ln 10 ≈...
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