Six Sigma

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1| Module: Module 6 / Topic: Distributions|
An event has historically averaged 1.4 occurrences per time period,what is the probability of exactly 4 occurrence(s) in a randomly selected time period of the same length?| you answered wrong and the Correct answer is 0.03947

Explanation:
In this case, probability of getting exactly 4 occurrences is obtained using the following function: =POISSON(4,1.4,0)| |  | | |
2| Module: Module 6 / Topic: Distributions| |
Given a normally distributed population with a mean of 392.84 and a standard deviation of 32.92.What is the probability of a randomly selected item having a value less than 314?| | you answered wrong and the Correct answer is 0.00831

Explanation:
=NORMDIST(314,392.84,32.92,1)| |
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3| Module: Module 6 / Topic: Distributions| |
A plant produces marbles, and 38.6% of all marbles produced are red. What is the probability of selecting less than or equal to 5 red marble(s) in a randomly selected sample of 9 marbles?| | you answered wrong and the Correct answer is 0.91500

Explanation:
Using the following function:=BINOMDIST(5,9,0.386,1)| |
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4| Module: Module 6 / Topic: Distributions| |
Given a normally distributed population with a mean of 361.2 and a standard deviation of 26.38. What is the probability of a randomly selected item having a value greater than 381.4?| | Correct| |

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5| Module: Module 6 / Topic: Distributions| |
A plant produces marbles, and 88.9% of all marbles produced are red. What is the probability of selecting more than 5 red marble(s) in a randomly selected sample of 10 marbles?| | Correct| |

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6| Module: Module 6 / Topic: Distributions| |
Given a normally distributed population with a mean of 417.43 and a standard deviation of 26.06. 72.91% is the probability of being less than what value?| | you answered wrong and the Correct answer is 433.32900

Explanation:
=NORMINV(0.7291,417.43,26.06)| |
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7| Module: Module 6 / Topic: Statistical Inference and ANOVA| | Given the results for each level of the factor below and using ANOVA, what is the value of the computed F-value for the main effect? AN19.xls| |

Correct| |
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8| Module: Module 6 / Topic: Statistical Inference and ANOVA| | Given the results for each level of the factor below and using ANOVA, what is the value of the computed F-value for the main effect? AN13.xls| |

Correct| |
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9| Module: Module 6 / Topic: Statistical Inference and ANOVA| | Given the results for each level of the factor below and using ANOVA, what is the value of the computed F-value for the main effect? AN12.xls| |

Correct| |
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10| Module: Module 6 / Topic: Statistical Inference and ANOVA| | Given the results for each level of the factor below and using ANOVA, what is the value of the mean square for the residual? AN44.xls| |

you answered wrong and the Correct answer is 1012.56001
Explanation:
Tools > Data Analysis… > Anova: Single Factor Within Groups is referred as the value of the mean square for the residual| |  | | |
11| Module: Module 6 / Topic: Statistical Inference and ANOVA| | Given the data in the table below, and assuming unequal variances, what is the value of the computed statistic for a hypothesis test to determine if the mean of the parts produced by Machine A is greater than the mean of the parts produced by Machine B? SI20.xls| |

Correct| |
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12| Module: Module 6 / Topic: Measurement Assurance| | Given the data in the 2 spreadsheets below, what is the linearity? Please DO NOT enter your answer as a percentage.For example enter a linearity of 0.004,not 0.4%. MA90.xls| |

you answered wrong and the Correct answer is 0.40010
Explanation:
Use Linearity.xls and Linearity.doc| |
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13| Module: Module 6 / Topic: Measurement Assurance| | Given the data in the...
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