I = current Q = net charge flowing t = time
1A 1C 1s

Unit: Q = Coulomb (C) I = Ampere (A) t = Second (s) Potential difference

Work done to move a unit charge from one point to another V W Q

Unit Volt 1 Volt
1 joule 1 coulomb 1V 1J C
1

Ohm’s law Current potential difference V I V = IR (R = resistance) Unit (R) 1 1V 1A

(Ohm)

Factors on which resistance depends 1. 2. R R l, when A and material constant l = length A, when l and material constant A = perpendicular cross-section

R R

l A l A

(

= resistivity)

Unit ( ) m Resistance in a series connection R = R1 + R2 + R3 + … + Rn Resistance in parallel 1 R 1 R1 1 R2 ... 1 Rn

Heating Effect of current Electric energy = VIt
Heat, H VIt I 2 Rt

Application Electric iron, toaster, fused wire Fused wire: a low-melting point wire connected in series with electric devices for safety. Electric power P VI I R
2

V2 R

Unit – 1 kWh = 3.6 × 106 J 1 W = 1V × 1A Definitions Potential difference: The potential difference between two separate points is defined as the work done to move a unit positive charge from one point to another.

Resistivity: Resistivity of a substance is equal to the resistance of a unit square of that substance. Law Ohm’ law: Under constant physical conditions (i.e., constant temperature, pressure etc.), the current flowing through a conductor is directly proportional to the potential difference across the conductor.

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...unit of a unit test charge transported between two points.
The electron volt is a unit of energy equal to approximately 1.6×10−19 joule (J). It is the amount of energy gained by the charge of a single electron moved across an electric potential difference of one volt. Thus it is 1 volt (1 joule per coulomb, 1 J/C) multiplied by the electron charge (1e, or 1.602176565(35)×10−19 C).
Electric current is the flow of charge (i.e. the + of batteries is charged...

...Dalton Leach
Physics 2 lab chapter 21
6/26/2015
Procedure Part I Wire Resistance:
As wire length (cm) increases, the resistance (Ω) increases
As wire area (cm2) increases, the resistance (Ω) decreases
As wire resistivity (Ωcm) increases, the resistance (Ω) increases
Procedure Part II: Ohm’s Law: Electricity, Magnets, and Circuits Ohm’s Law
mA is milliamps, and 1000 milliamps equals one Ampere.
Move the potential (volts) and resistance (ohms) sliders and...

...Assuming that the Earth is a uniform sphere of radius 6.4 x 106 m and mass 6.0 x 1024 kg, find the gravitational field strength g at a point:
(a) on the surface,
g = GM / r2 = (6.67 × 10-11)(6.0 x 1024) / (6.4 x 106)2 = 9.77ms-2
(b) at height 0.50 times the radius of above the Earth's surface.
g = GM / r2 = (6.67 × 10-11)(6.0 x 1024) / ( (1.5 × 6.4 x 106)2 = 4.34ms-2
Example 2:
The acceleration due to gravity at the Earth's surface is 9.80ms-2. Calculate the...

...* Electric charge exists as discrete “packets”
* Q=NE where N is the some integer, e is the charge of an electron
* The charge of a single electron e is e=1.602x10^-19C, where the Coulomb (C) is the unit of charge
* Eg: determine 10 electrons= 10 x 1.602.10^19
Outline 4 properties of electric charge:
* unlike charges attract
* like charges repel
* charge is conserved
* charge is quantized.
Coulombs Law
Coulomb’s law is...

...60x10-19C.
2.1.3
Field strength is equal to force per unit charge. The SI unit for field strength is NC-1 or
Newtons per coulomb.
Rearranging that formula can give us the force (F) acting upon a point charge (of
charge Q) in a field of strength E: F=EQ
NOTE: Both field strength and force are vectors, while charge is a scalar. By vector
addition it is possible to predict the effect of an electric field on a point charge.
2.1.4
Electric current is defined to be the rate at...

...Chapter10 Power Supplies
Measuring Electricity
Voltage—pressure of electrons in a wire
Unit of measurement: volts (V)
Current— flow (or amount) of electrons in a wire
-Unit: ampere (A)
-When voltage is applied to a wire, electrons flow, producing current
Wattage—measure of power consumed or needed
watt (W) W = V * A
Resistance—impedance or opposition to the flow
ohm (Ω)
Wire has amperage rating
Defines how much amperage it can handle
i.e., 20 amp, 30...

...CHAPTER10
(#1) SUBTOPIC >> SEXUAL DISORDER
(1) There are Sexual desire Disorder
Male hypoactive sexual desire disorder
Female sexual interest/arousal
(2) females are higher in finding out from the clinic
males have higher erectile dysfunction as older the age
(overview slide of sexual dysfunction)
female arousal disorders tend to be easier to hide than male disorder
(3) orgasm disorder are more common in woman and occur in the orgasm phase
for...

...Experiment No: EM-1 Title: Ohm’s Law, Meters, Resistivity
I Purpose:
The basic of simple electrical circuits and measurements is learned. Also, investigating the dependence of the resistance of a wire on its length, cross-sectional area, and the material of which it is made. By examining electrical resistance (R) through a metal conductor, the voltage (V) and current (I) through the conductor, the following principles will be demonstrated:
1.) Ohm’s Law
2.) Dependence of...

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