Result of Observation: Flame Test

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Result of Observation
Chemical name and symbolPhysical appearanceCation of the compoundFlame color NaNO3Sodium nitrateColourless crystalNa+Yellowish Orange
NaClSodium chlorideColorless crystalCl+Yellowish Orange
LiNO3Lithium nitrateColorless crystalLi+Red
BaNO3Barium nitrateWhite crystalBa²Bright yellow, lime yellow Sr(NO3) 2Strontium nitrateWhite crystalSr²Dark red
Cu(NO3)2Cupric nitrateBlue crystalCu²Green, bluish green. Ca(NO3) 2Calcium nitrateWhite crystalCa²Redish orange
KNO3Potassium nitrateColourless crystal.K+Light purple
Unknown #1Colorless crystalRed
Unknown #2White crystalRedish orange
Unknown #1 is lithium nitrate, because it had the same physical appearance and same flame color as lithium nitrate. Unknown #2 is calcium nitrate, because they share the same physical appearance and flame color. Discussion

A)Which part of the compound is responsible for the flame colour? How would you know?

The cation part of the compound is responsible for the flame colour. Because almost all of the different compound had nitrate as the anion, but they had different colours. The only compound which did not have nitrate, as the anion is sodium chloride. But it produced the same color as sodium nitrate, which showed that the color in which they produce was caused by sodium.

B)Which sample released the most energy? How would you know?

The sample, which released the most amount of energy, is potassium nitrate. Because the amount of energy light produces is depended on the frequency (colour) of the light, and potassium nitrate produced a light purple colour. According to the visible spectrum, a photon of purple had more energy than any other colour produced in this lab, because purple light has shorter wavelength (approximately 380-450 nm) and shorter wavelength means higher frequency which also means higher energy. Therefore we can conclude that potassium nitrate produced the most amount of energy when burned. C)How...
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