Relative Frequency Of A Category Frequency
Relative frequency of a category =
Frequency of that category
Sum of all frequencies
Class width = Upper boundary– Lower boundary
Class midpoint or mark = Lower limit+ Upper limit/2
Approximate class width=Largest value -mallest value / Number of classes
Relative frequency of a class=Frequency of that class/Sum of all frequencies
Cumulative relative frequency=Cumulative frequency of a class/Total observations in the data set
Mean = Average , Median , Mode
Range = Largest value– Smallest Value
Variance and Standard Deviation
Variance and Standard Deviation for Grouped Data
Smallest value within the two inner fences = 69
Largest value within the two inner fences = 112
Eg, Refer to the data on total compensations (in millions of dollars) for the year 2010 of the 12 highest companies given in Example 3-20. Find the value of the 60th percentile. Give a brief interpretation of the 60th percentile.
21.6 21.7 22.9 25.2 26.5 28.0 28.2 32.6 32.9 70.1 76.1 84.5
The position of the 60th percentile is
Conditional probability is the probability that an event will occur given that another has already occurred. If A and B are two events, then the conditional probability A given B is written as P ( A | B ) and read as “the probability of A given that B has already occurred.”
We are to calculate the probability of the intersection of the events F and G. P(F and G) = P(F) P(G |F)
P(F) = 13/40 P(G |F) = 4/13
P(F and G) = P(F) P(G |F) = (13/40)(4/13) = .100
Union of Events
P(A or B) = P(A) + P(B) – P(A and B)
Let us define the following events:
A = the person selected is a faculty member
B = the person selected is in favor of the proposal
P(A) = 70/300 = .2333 P(B) = 135/300 = .4500
P(A and B) = P(A) P(B | A) = (70/300)(45/70) = .1500
P(A or B) = P(A) + P(B) – P(A and B) = .2333 + .4500 – .1500 = .5333
EX, The probability that a person is in favor of genetic engineering is .55 and that a person is against it is .45. Two
Frequency of that category
Sum of all frequencies
Class width = Upper boundary– Lower boundary
Class midpoint or mark = Lower limit+ Upper limit/2
Approximate class width=Largest value -mallest value / Number of classes
Relative frequency of a class=Frequency of that class/Sum of all frequencies
Cumulative relative frequency=Cumulative frequency of a class/Total observations in the data set
Mean = Average , Median , Mode
Range = Largest value– Smallest Value
Variance and Standard Deviation
Variance and Standard Deviation for Grouped Data
Smallest value within the two inner fences = 69
Largest value within the two inner fences = 112
Eg, Refer to the data on total compensations (in millions of dollars) for the year 2010 of the 12 highest companies given in Example 3-20. Find the value of the 60th percentile. Give a brief interpretation of the 60th percentile.
21.6 21.7 22.9 25.2 26.5 28.0 28.2 32.6 32.9 70.1 76.1 84.5
The position of the 60th percentile is
Conditional probability is the probability that an event will occur given that another has already occurred. If A and B are two events, then the conditional probability A given B is written as P ( A | B ) and read as “the probability of A given that B has already occurred.”
We are to calculate the probability of the intersection of the events F and G. P(F and G) = P(F) P(G |F)
P(F) = 13/40 P(G |F) = 4/13
P(F and G) = P(F) P(G |F) = (13/40)(4/13) = .100
Union of Events
P(A or B) = P(A) + P(B) – P(A and B)
Let us define the following events:
A = the person selected is a faculty member
B = the person selected is in favor of the proposal
P(A) = 70/300 = .2333 P(B) = 135/300 = .4500
P(A and B) = P(A) P(B | A) = (70/300)(45/70) = .1500
P(A or B) = P(A) + P(B) – P(A and B) = .2333 + .4500 – .1500 = .5333
EX, The probability that a person is in favor of genetic engineering is .55 and that a person is against it is .45. Two