# Quantitative Methods and Analysis

Part I

a) What is the gender distribution (%females and %males)?

Solution. From the database, we know that there are 168 female people, 120 male people among 288 people. So,

168/288=58.33% is female, 120/288=41.67% is male.

b) What is the “tenure with company” distribution by gender? We look at all males. You can do that for females similarly. We get the following table.

From this table, we know that there are 120 males:

26 with code 2 meaning they stay in the company for 2 to 5 years.” 14 with code 3 meaning they stay in the company over 5 years” 80 with code 1 meaning they stay in the company for less than 2 years So, the “tenure with company” distribution by male is

26/120=21.67% among 120 males stays in the company for 2 to 5 years. 14/120=11.67% among 120 males stays in the company over 5 years; 80/120=66.66% among 120 males stays in the company for less than 2 years. c) What % of the survey participants are in each department? By the database, we know that 11 people from the department 1; 100 people from the department 2; 177 people from the department 3; So, 11/288=3.8% from the department 1;

100/288=34.7% from the department 2;

177/288=61.5% from the department 3.

d) What is the mean overall satisfaction by gender?

We get a table for male.

Column1

Mean4.430833...

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