# Projectile Motion

Topics: Basketball, Velocity, Force Pages: 9 (1426 words) Published: April 17, 2013

By:
Fieda Rizkiana
09/X11

SENIOR HIGH SCHOOL 2 KEDIRI
2013
ACKNOWLEDGEMENT

The writer expresses her gratitude to Allah SWT for blessing, love, opportunity, health and mercy to complete this assignment entitled “PROJECTILE MOTION AND BASKET BALL” to complete final task of Physics in 2nd semester. To complete this assignment, the writer knows that without other people’s help and support she will never be able to finish it. Therefore, writer would like to express her gratitude to everyone who helped her. The writer realizes that this assignment is far for being perfect, so suggestion and criticism for the perfection of this assignment will be the most welcome and accepted with pleasant and gratitude. Finally, she hopes that this Physics assignment will be usefull for the readers and especially for herself.

Kediri, 27th of February 2013

The Writer
TABEL OF CONTENT

Cover Page i
Acknowledgement ii
Table of Content iii
CHAPTER I INTRODUCTION 1
A. Purpose 1
B. Background1
C. Material 1
D. Procedure 2
CHAPTER II DISCUSSION3
A. Result of Experiment 3
B. Analysis 4
CHAPTER III CONCLUSION AND SUGGESTION 15
Bibliography 16
CHAPTER I INTRODUCTION
PURPOSE
The purpose of this experiment is:
1. Knowing the work of projectile motion in basket ball
2. Knowing the V0
3. Knowing the t

BACKGROUND
In order to figure out the perfect shot, you are going to need to know what projectile motion is. So really, what is projectile motion? Projectile motion is the curved path (also known as a parabola) an object follows when thrown near the surface of the Earth. It has an initial velocity, but after that, the only force acting on the object is gravity. In order to figure out the perfect shot, you are going to need to know what projectile motion is. So really, what is projectile motion? Projectile motion is the curved path (also known as a parabola) an object follows when thrown near the surface of the Earth. It has an initial velocity, but after that, the only force acting on the object is gravity.

MATERIAL
2. Meter roll
3. Notebook and pen to write the result

PROCEDURE
1. Measure:
a. height of ring
b. height of thrower
c. distance between ring and thrower
2. Thrower shoot basket ball toward the ring with the specified distance 3. Write the data from the measurement
4. Analyze the data to find a value of velocity and time needed

CHAPTER II

DATA OF EXPERIMENT
Hr
Ht
Yf
X
Vo

Explanation:
V0= initial velocity
θ= angle
X= horizontal distance between thrower and ring
Ht= the height of thrower
Hr= the height of ring
Yf= the difference between height of ring and height of thrower

Experiment| Shot 1| Shot 2| Shot 3| Shot 4| Shot 5|
X| 6.3 m| 5.6 m| 4.6 m| 3.8 m| 2.75 m|
Yf| 1.51 m| 1.51 m| 1.51 m| 1.51 m| 1.51 m|
Ht| 1.49 m| 1.49 m| 1.49 m| 1.49 m| 1.49 m|
Hr| 3 m| 3 m| 3 m| 3 m| 3 m|

ANALYSIS
Shooting a basketball can be described as a projectile motion. When the object was thrown, the velocity will become zero once it reach the highest point, after that the ball will continue to move forward because the horizontal force still exists. It will continue to move forward until it hit the ground, due to the gravity.

So to figure out the perfect angle to shoot the ball at, we will have to use reverse trigonometry. Since we were given the Vix and the Viy, you will need to use the reverse of tangent, also known as arctangent.

Data I
X1= 6.3 m
Ht= 1.49
Hr = 3 m
Yf= 3 - 1.49
= 1.51 m

Tan θ= Yfx1
Tan θ= 1.516.3
Tan θ= 0.2396825397
θ= 13.47853354°

yf= vo2×sin2θ2g
1.51= vo2×sin213.47853354°2 . 9.8
1.51×19.6= vo2×0.05432677
vo2=29.5960.05432677
vo=544.777457
vo=23.34046822 m/s

t= v0×sinθg
t= 23.34046822 ×0.2330810399.8
t=5.4402205839.8...