Projectile
TITLE:
Trajectory of a Projectiles
PROBLEM STATEMENT:
A spherical ball was projected from a fixed point ,O, with a speed ,u, angels of elevation : 0, 10, 20, 30, 40, 50, 60, 70, 80, 90 to the horizontal ground surface. Find the value of maximum height travelled by the ball for which the horizontal range, R, greatest for the same value of u.
AIM:
To investigate:
1)Range of projected ball.
2)Time of flight for corresponding angel of projection
METHODOLOGY:
APPARATUS AND MATERIALS USED:
1)Projectile launcher
2)measuring tape
3)stop watch
4)chalk
DIAGRAM:
Illustration showing how apparatus was set up:
METHOD USED TO CONDUCT EXPERIMENT:
1)The apparatus was set up as shown in the diagram by raising the trigger mechanism with one hand and using the alternate hand, to push the attached ball into the shaft, the screw on the bar was adjusted to produce an appropriate force. This remain stationary to produce a constant force for the projection.
2)The protractor built into the projectile launcher was adjusted to zero degrees.
3)The trigger was pulled , simultaneously starting the stop watch.
4)When the spherical ball hit the horizontal ground surface the stopwatch was stopped. The distance from the projector to where the ball landed was measured.
5)The time of flight was recorded together the distance (range) was recorded.
6)Steps 2-5 were repeated two more times
7)The previous process was repeated ,each for the displacement of the spherical ball at 10,20,30,40,50,60,70,80,90 degrees
8) An average for the distance an time of flight by the spherical ball was calculated. The data collected was tabulated .Graphs of Time of Flight vs Angle ,together with , Range vs Angel was plotted.
Theory:
Projectile motion is the motion of an object into the air at an angel. The object in motion is referred to as a projectile ,in this experiment , the small spherical
Trajectory of a Projectiles
PROBLEM STATEMENT:
A spherical ball was projected from a fixed point ,O, with a speed ,u, angels of elevation : 0, 10, 20, 30, 40, 50, 60, 70, 80, 90 to the horizontal ground surface. Find the value of maximum height travelled by the ball for which the horizontal range, R, greatest for the same value of u.
AIM:
To investigate:
1)Range of projected ball.
2)Time of flight for corresponding angel of projection
METHODOLOGY:
APPARATUS AND MATERIALS USED:
1)Projectile launcher
2)measuring tape
3)stop watch
4)chalk
DIAGRAM:
Illustration showing how apparatus was set up:
METHOD USED TO CONDUCT EXPERIMENT:
1)The apparatus was set up as shown in the diagram by raising the trigger mechanism with one hand and using the alternate hand, to push the attached ball into the shaft, the screw on the bar was adjusted to produce an appropriate force. This remain stationary to produce a constant force for the projection.
2)The protractor built into the projectile launcher was adjusted to zero degrees.
3)The trigger was pulled , simultaneously starting the stop watch.
4)When the spherical ball hit the horizontal ground surface the stopwatch was stopped. The distance from the projector to where the ball landed was measured.
5)The time of flight was recorded together the distance (range) was recorded.
6)Steps 2-5 were repeated two more times
7)The previous process was repeated ,each for the displacement of the spherical ball at 10,20,30,40,50,60,70,80,90 degrees
8) An average for the distance an time of flight by the spherical ball was calculated. The data collected was tabulated .Graphs of Time of Flight vs Angle ,together with , Range vs Angel was plotted.
Theory:
Projectile motion is the motion of an object into the air at an angel. The object in motion is referred to as a projectile ,in this experiment , the small spherical