A farmer is taking her eggs to the market in a cart, but she hits a Pothole, which knocks over all the containers of eggs. When she put the eggs in groups of two, three, four, five, and six there was one egg left over, but when she put them in groups of seven they ended up in complete groups with no eggs left over. Now she needs to know how many eggs she had and is there more than one possibility.
The first thing I did was to read the pow aging on my own. I out when she put her eggs in groups of two there is one left over. The number cannot be a multiple of two. Also three four five and six can’t be a multiple of this number. If there were no eggs left over when put into groups of seven there must have been a multiple of 7 eggs. Now need to find multiples of seven. 7,14,21,28,35,42,49,56,63,70,77, 84,91,98, 105,112,119,126,133,140,147 ,154,161,168,175,1 82 ,189,196 ,203 ,210, 217, 224, 231 ,238, 245, 252 ,259, 266, 273, 280,287,294,301 Then you cross out all the numbers that are divisible by 2,3,4,5, and 6. So I got161 and 301 as the numbers that cannot be multiples 2, 3,4,5,6.
| 3 * 4 * 7 = 8449 + 84 = 133. No good. 133 is not good because it is not a multiple of 7133 + 84 = 217. No good. 217 because it is not a multiple of 7217 + 84 = 301. Good| | |
I got 301 because you get a remainder of 1 for the numbers: 2,3,4,5 and 6. So the smallest number of eggs is 301. But there is other solution. But usually what you're looking for is the smallest solution, so 301 is probably the answer you want.
One day a boy was going to the basketball court he had six sets of balls. When he was getting there he trip on a rock letting all the ball falling out the net. Now he needs to found out how many balls were in the nets. He know when he put the balls in groups two, three, four, five and six three was one ball left over, but when she put them in group of seven they end up a complete groups with no eggs left over....