POW #13 Corey Camel
Problem Statement: Corey the Camel has a small banana grove in the desert, her harvest this year was 3,000 bananas. The market where Corey sells her bananas is 1,000 miles away. Corey has to walk to the market to sell her bananas, for each mile Corey walks, she eats one banana. Corey can only carry 1,000 bananas at a time. In this POW the goal is to find the number of bananas that Corey can get to the market. Process: To find the answer to this POW I did the mini POW, as suggested. I used the same process for POW 13, as I did for the mini POW. The process is as follows: 1. Corey starts the trip with 1,000 bananas.

2. She travels 200 miles, she’s left with 800 bananas. She stashes 600 bananas at 200 mile point, keeping 200 the trip back. 3. Corey picks up another 1,000 bananas.
4. She travels 200 miles, she has 800 left. She then picks up 200 from the bananas stashed. She now carries 1000 bananas and has 400 more stashed. 5. She travels an additional 333 1/3 miles, she’s left with 666 2/3 bananas, she stashes 333 1/3 there (533 1/3 mile point), she has 333 1/3 bananas left. 6. She then travels back 333 1/3 miles to 200 mile point. She has no bananas left, so picks up 200 stashed (leaving 200 still at 200 mile point), and travels back to the grove, 200 miles away. 7. She picks up another 1,000 bananas at the grove.

8. She travels to the 200 mile point, leaving her with 800 bananas, she picks up remaining 200 stashed. 9. With 1,000 bananas, she travels 333 1/3 miles to 533 1/3 mile point, she is then left with 666 2/3 bananas. 10. She picks up all 333 1/3 that were stashed there

11. She’s back at 1000 bananas
12. She makes remaining 466 2/3 mile trip, 1000-466 2/3 = 533 1/3 bananas left to sell at the market. Solution:
a. Corey the Camel will have 533 1/3 bananas to sell at the market. b. Yes, I do think that my solution is the best possible, because if you try stashing less bananas at the 200 mile point, or traveling further...

...Problem Statement:
CoreyCamel has 3,000 bananas in her small banana grove in the desert. The marketplace where Corey sells her bananas is 1,000 miles away. Corey has to walk to the market to sell her bananas. For every mile that Corey walks, she must eat 1 banana. Corey can only carry 1,000 bananas at one time. For POW13, I have to figure out how many bananasCorey can get to the market.
Process
To solve POW13, I first worked on a mini-POW to help me figure out POW13. I used the same process in POW13 as I did in a mini-POW. The process is as follows:
1. Corey picks up 1,000 of the bananas, travels 200 miles, and drop 600 bananas at the 200 mile point. There are 200 bananas left for the trip back.
2. Pick up 1,000 more bananas, travel 200 miles, pick up 200 of the bananas that Corey dropped earlier. (Corey now has 1,000 bananas again.)
3. Travel an additional 333 1/3 miles. (533 1/3 mile point) Corey now has 666 2/3 bananas. Drop 333 1/3 bananas there and travel back 333 1/3 miles to the 200 mile point.
4. Pick up the 200 bananas that were dropped there earlier and head back...

...POW13: CoreyCamel
By Alex Cohen
Problem Statement: CoreyCamel has 3,000 bananas to take to the market. He can only carry 1,000 at a time. The market is 1,000 miles away. Every mile Corey eats a banana. My job is to find out; how many bananas he can get to the market place?
Process: To do this POW I started with Mini Camel to find a good strategy. The strategy we found was this: take as many bananas as you can to a certain distance and drop the rest, minus enough to get back. For example go 100 miles, drop 800, then come back 100 miles, you have used all of your bananas. Next I applied this method to CoreyCamel, and since our teacher said the most number of bananas he can bring back was 533 1/3 I realized that after the 1st 1,000 were gone, I would use the other 2,000 by dividing them into 1/3s since the only way to get 33 1/3 is to divide something by 3, like 1,000 divided by 3 is 333 1/3. 533 333 is 200, so I know that the 1st trip has to evolve 200, since I need 200 to be left over when I'm done to get me the rest of the way. I drew out a time line of events to show Corey's movements as he progresses.
Solution: Corey starts by picking up 1,000 bananas, and walking them 200 miles. Next he drops 600 and goes back 200. After that he picks...

...1. To find my conclusions I had to think about each part of the problem. When you know that one thing means you go on to the next part. When you figure out what that means you have to see how the two statements are related. If they are related then you can deduce a conclusion that makes sense.
2. Here are my conclusions for the 6 problems on page 7.
1. a. No medicine is nice
b. Senna is a medicine
Here I deduced that Senna is not a nice medicine. I think this because the first statement says that “no medicine is nice.” That tells me that all medicines are not nice. The second statement says “Senna is a medicine”. That statement is straight forward. When you put them together you can decide that Senna is a medicine and medicines are not nice. So Senna is not nice.
2. a. All shillings are round
b. These coins are round
Here I decided that no now conclusions can be drawn. The first statement says “All shillings are round.” That statement is clear. The second statement says “These coins are round.” This tells you the coin they have are round. When you put these statements together you can see some flaws. They say these coins but you don’t know if any of these coins are shillings. They can be other coins that are round. So you cannot deduce anything.
These coins are
3. a. Some pigs are wild
b. All pigs are fat
Here I decided that there are no conclusions that can be made. The first...

...“A Sticky Gum Problem” POW 4
Problem statement:
The next scenario is very similar. In this one, Ms. Hernandez passed a different gumball machine the next day with three different colors Once again her twins each want a gumball of the same color, and each gumball is still one cent. What is the most amount of money that Ms. Hernandez would have to spend in order to get each of her daughters the same color gumball?
In the last scenario, Mr. Hodges and his triplets pass the same gumball machine that Ms. Hernandez and her twins passed in scenario two. This time, each of Mr. Hodges children wants the same color gumball out of the three-color gumball machine. What is the most amount of money that Mr. Hodges would have to spend on his triplets in order to get them each the same color gumballs?
Process:
In the process of solving the first question I drew up different color gumballs.
These are both the different colored gumballs. If this was the outcome after spending two pennies on two gumballs, then the next gumball would have to be one of the previous color gumballs that already came out of the machine.
For the next scenario it was a little trickier that the first problem. Since there were still only two children involved and there were three colored gumballs it wasn’t too hard. Once again, I drew up the three different colored gumballs in the gumball machine. The gumballs were red, white, and...

...Jason Vo
Ms. King
3/11/15
Period 1
Due Date: 3/13/15
Corey’s CamelsPOW
Problem Statement
The problem basically is about a camel named Corey that has to carry 3000 bananas to a place 1000 miles away. But, Corey can only carry 1000 bananas and Corey has to eat one banana for every mile she walks/runs/skips/hops, etc. In addition to that, there is a refrigerator at every mile. So the question being asked is how many bananas can Corey get to the market with all these requirements?
Strategy
My strategy for this problem is to make some sort of a chart and/or explain the POW in steps. I will explain the problem in a clear and understandable way to make sure the person reading it will understand it and how the problem is very complicated/easy.
Problem Process
Once I read the problem, I knew you had to think outside the box, but I wasn’t sure how. So I started off like this:
Number of Bananas Corey is carrying
Number of Bananas dropped off and at which mile
Number of bananas left/needed for the returning trip
1000
200th: 600 bananas
200 bananas
1000
200th: 600 bananas
200 bananas
1000
200th: 800 bananas
0 bananas
1000
600th: 200 bananas
400 bananas
1000
600th: 200 bananas
0 bananas
Solution
Evaluation
I think I would rate the...

...Mega POW
A very wealthy king has 8 bags of gold, which he trusts to some of his caretakers. All the bags have equal weight and contain the same amount of gold, all the gold in the kingdom. Although, the king heard a story that a woman received a gold coin. The king knew it had to be his gold so he wanted to find the lightest bag in the 3 weighing, but the mathematician thought it could be done in less, so I need to find out the least amount of weighing it takes to find the lightest bag. Also, the king used a pan balance for all of his weighing.
I started by weighing 4 bags on each side of the scale to see which side was lighter. Then from those results I thought to weigh the 4 bags that were on the lighter side by 2 and 2. After this you would find one side weighing less than another. Then you would take those results and weigh the 2 remaining bags and the lightest bag would be the bag that was taken from. However, the mathematician said it could be done in less than three steps. So throwing the answer I had just gotten to the side, I started new. This time I started with 3 bags on each side knowing that if two sides were equal than the bag with the missing gold would be one of the bags not weighed the first time. Then you would have to weigh the two remaining bags and whichever one was lighter than the other would be the bag with less gold. But, if the 3 bags from the beginning weighed different then you would weigh 2 bags of the 3 and if they are equal...

...probability of success or the one most likely to help me win.
Strategy # 1
a. Always choose the same thing the card says. So if it is an O choose O, if it is an X choose X.
b. 30 trials
1. yes 6.no 11.no 16.yes 21.yes 26. yes
2. yes 7.yes 12.yes 17.yes 22.no 27. yes
3. yes 8.no 13.yes 18.no 23.yes 28. yes
4. no 9.no 14.yes 19.yes 24.no 29. yes
5.no 10.yes 15.yes 20.no 25.no 30. Yes
P (right) – 18/30 or 6/10 or .6
Success rate = .6
c. (XX)-works-1/6
(XX)-works-1/6
(OO)-works-1/6
(OO)-works-1/6
(OX)-doesn’t work
(XO)-doesn’t work total successful – 4/6 or 2/3 or .66
Success rate = .66
Strategy #2
a. Always choose O no matter what.
b. 30 trials
1. yes 6.no 11.yes 16.yes 21.no 26.yes
2. yes 7.no 12.yes 17.yes 22.no 27.no
3. no 8.yes 13.no 18.yes 23.no 28.yes
4. no 9.no 14.yes 19.yes 24.yes 29.yes
5.no 10.yes 15.yes 20.yes 25.no 30.no
P (right) – 17/30 or .56
Success rate = .56
c. (XX)-doesn’t work
(XX)-doesn’t work
(OX)-doesn’t work
(XO)-works-1/6
(OO)-works-1/6
(OO)-works-1/6 total successful – 3/6 or .5
Success rate = .5
Strategy # 3
a. Always...

...CoreyCamel
Problem Statement CoreyCamel owns a banana grove with 3000 bananas on it. She can only carry 1000 bananas at a time. The market where she can sell her bananas is 1000 miles away. Sounds easy right? Wait there’s a catch. For every mile she walks she has to eat one banana. See now it got hard. So with all of this said how many bananas will he be able to take to the market and sell?
Process Doing the miniPOW helped a lot with this one. Because knowing that CoreyCamel can drop bananas on the way to the market is an important part, because of he couldn’t the answer would be an obvious zero. Since you can drop them I decided to drop 800 bananas at the 100 mile point. That way she can eat her 100 bananas that she needs to on her way there and still have another 100 to get back to her banana grove. When she gets there she’ll have 900 new bananas. The only problem is that she can only carry 1,000 bananas at a time. So she takes 1,000 bananas the rest of the way. This would leave her with 100 bananas. Then I realized that wasn’t the largest amount that she could sell. So I started to work backwards from 500 miles. I did this because 500 is half of 1,000. The only problem with 500 is that she would use 500 bananas to get there and wouldn’t be able to drop any bananas because she would have to use the last 500 bananas to get back. So I started to work with 400...