Corey Camel has 3,000 bananas in her small banana grove in the desert. The marketplace where Corey sells her bananas is 1,000 miles away. Corey has to walk to the market to sell her bananas. For every mile that Corey walks, she must eat 1 banana. Corey can only carry 1,000 bananas at one time. For POW 13, I have to figure out how many bananas Corey can get to the market.

Process

To solve POW 13, I first worked on a mini-POW to help me figure out POW 13. I used the same process in POW 13 as I did in a mini-POW. The process is as follows:

1. Corey picks up 1,000 of the bananas, travels 200 miles, and drop 600 bananas at the 200 mile point. There are 200 bananas left for the trip back.

2. Pick up 1,000 more bananas, travel 200 miles, pick up 200 of the bananas that Corey dropped earlier. (Corey now has 1,000 bananas again.)

3. Travel an additional 333 1/3 miles. (533 1/3 mile point) Corey now has 666 2/3 bananas. Drop 333 1/3 bananas there and travel back 333 1/3 miles to the 200 mile point.

4. Pick up the 200 bananas that were dropped there earlier and head back to the banana grove.

5. Pick up another 1,000 bananas. Travel back to the 200 mile point. Drop 800 bananas and pick up the remaining 200 bananas that were dropped there earlier.

6. With the 1,000 bananas, travel 333 1/3 miles to the 533 1/3 mile point. You now have 666 2/3 bananas. Pick up the bananas you dropped at this point earlier and now you have 1,000 bananas again.

7. Travel the remaining 466 2/3 mile trip to the market. 1,000 - 466 2/3 = 533 1/3 bananas.

Solution:

a.Corey Camel will have 533 1/3 bananas when she gets to the market. b.Yes, I think that this solution is the best possible one, because if you try it with Corey leaving less bananas at the 200 mile mark or if you try it with Corey traveling out farther than the 200 mile mark for the first step then Corey always ends up falling short of bananas on the way to the market. 533 1/3...

...POW13: CoreyCamel
By Alex Cohen
Problem Statement: CoreyCamel has 3,000 bananas to take to the market. He can only carry 1,000 at a time. The market is 1,000 miles away. Every mile Corey eats a banana. My job is to find out; how many bananas he can get to the market place?
Process: To do this POW I started with Mini Camel to find a good strategy. The strategy...

...POW #13CoreyCamel
Problem Statement: Corey the Camel has a small banana grove in the desert, her harvest this year was 3,000 bananas. The market where Corey sells her bananas is 1,000 miles away. Corey has to walk to the market to sell her bananas, for each mile Corey walks, she eats one banana. Corey can only carry 1,000 bananas at a time. In this...

...CoreyCamel
Problem Statement CoreyCamel owns a banana grove with 3000 bananas on it. She can only carry 1000 bananas at a time. The market where she can sell her bananas is 1000 miles away. Sounds easy right? Wait there’s a catch. For every mile she walks she has to eat one banana. See now it got hard. So with all of this said how many bananas will he be able to take to the market and sell?
Process Doing the mini...

...Problem Statement
Corey the camel has 3,000 bananas. He has to deliver the bananas 1,000 miles to the market. For every mile Corey travels, he eats one banana. Corey can only carry 1,000 bananas at one time. For this problem I have to find out how many bananas Corey delivers to the market.
Process
For my process I used the maximum number of bananas Corey could carry per trip, which were 1,000 bananas in...

...POW #13
Problem: This POW’s problem was to have seven spaces, three of which were shaded, 1 empty space, then three spaces that were plain. The object was to switch the colors to the opposite side, but while doing this you could only move your marker to an adjacent space, or jump over ONE marker to another open space.
Process: I used pennies in place of the plain markers, and nickels in place of the shaded markers. I started by randomly moving blocks around...

...Ian deGrouchy
Mrs. Psitos
Math IMP 2H
18 December 2007
Growth of Rat Populations
This POW is about the growth of a rat population over a year. Two rats, one male and one female, are put on an island that has ideal conditions for rats. The female rat has a litter of six rats the first day, and will have a litter every forty days after that. There are three important things to remember, and they are that the number of rats in every litter is six, three females and...

...POW 15 Growth of rat populations Problem Statement This problem is composed of the growth of a rat population over the course of one year from 2 rats. Four assumptions for this problem were made: Each new liter is composed of 6 rats; 3 males, 3 females. The original pair give birth to 6 rats on the first day and then ever 40 days after. There is a 120 day "gestation" period before a newborn rat can reproduce. After this gestation period the rats will give birth every 40 days....

...Pow 2
Problem Statement:
There’s a standard 8 x 8 checkerboard made up by 64 small squares. Each square is able to combine with others squares to make other squares of different sizes. Our job is to find out how many squares there’s in total. Once you get all the number of squares get all the number of squares and feel confident with your answer you next explain how to find the number of...

## Share this Document

Let your classmates know about this document and more at StudyMode.com