REVIEW EXERCISES
CHAPTER 8 AND 9
PROFESSOR JONAS
WIURES
BY DEBRA JAMES
CHAPTER 8
1. High temperature in the United States a meteorologist claims that the average of the highest temperatures in the united states in 98. A random sample of 50 cities is selected, and the highest temperatures are recorded. The data are shown. At a=0.05 can the claim be rejected? a=7.7 97, 101, 99, 99, 100, 94, 87, 99, 108, 93, 96, 88, 98, 97,88, 105, 97, 96, 98, 102, 99, 94, 96, 114, 99, 96, 98, 97, 91, 98, 80, 95, 98, 96, 80, 95, 88, 99, 102, 95, 101, 94, 92, 99, 101, 97, 94, 97, 102, 61. The claim can be rejected; correct answer may be either above 98 or below it.
2. Salaries for Actuaries nationwide graduates entering the actuarial field earn $40,000. A college placement officer feels that this number is too low. She surveys 36 graduates entering the actuarial field and finds the average salary to be $41,000. The population standard deviation is $3000. Can her claim be supported at 0.05?
x¯=14.7, μx¯=13.77, ox¯=5.34, n=29, α=.01
3. Monthly Home Rent. The average monthly rent for a one bedroom in San Francisco is $ 1229. A random sample of 15 one bedroom homes about 15 miles outside of San Francisco had a mean rent of $1350. The population standard deviation is $250. At a=0.05 can we conclude that the monthly rent outside San Francisco differs from that in the city? 4.
5. Federal Prison Populations nationally 60.2% of federal prisons are severing time for drug offenses. A warden feels that in his prisons the percentage is even higher. He surveys 400 inmates records and finds that 260 of the inmates are drug offenders at a=0.05 is this correct?
CHAPTER 9
1.
Driving for pleasure  two groups of drivers is surveyed to see how many miles per week they drive for pleasure trips. The data are shown at a=0.01 can it be conducted that single drivers do more driving for pleasure trips on average than married drivers? Assume =16.7 and =16.1 Level...
...histogram of the 1990 returns.
(ii) Produce a histogram of the 1998 returns.
(iii) Find the mean, median, range and standarddeviation for the 1990 returns.
Annual Returns % (1990)
Mean 12.91865979
Median 11.38
StandardDeviation 9.297513067
Range 75.01
(iv) Repeat part (iii) for the 1998 returns.
Annual Returns % (1998)
Mean 6.355463918
Median 5.4
StandardDeviation 5.170830853
Range...
...specific statistical results that would help a real estate agent understand the condominium market. 4. A 95% confidence interval estimate of the population mean sales price and population mean number of days to sell for Gulf View condominiums. Also, interpret the results. 5. A 95% confidence interval estimate of the population mean sales price and population mean number of days to sell for Gulf View condominiums. Also, interpret the...
... To determine if the average number of calories in a serving of popcorn is different from 75, a nutritionist selected a random sample of 20 servings of popcorn and computed the sample mean number of calories per serving to be 78 with a sample standarddeviation of 7.
State the null and alternative hypotheses. 

 A. H0: = 75, H1: ≠ 75  

 B. H0: 75, H1: > 75  

 C. H0: 75, H1: < 75  

 D. H0: = 75, H1:...
...Practical 16: estimating Population Size Using Mark and Recapture Method
Raw and Processed Data
Table 1: Uncertainties of apparatus used in the experiment.
Apparatus  Uncertainties 
Stopwatch  ±0.01s 
Table 2: Formulae and sample calculations involved in processing data in the experiment.
Calculations  Formula  Sample Calculation 
Mean
( x )  x = 1n i=1naiWhere, 1. n refers to the total number of values. 2. ∑ refers to the addition of all values...
...Inferences for One PopulationStandardDeviation
The Standarddeviation is a measure of the variation (or spread) of a data set. For a variable x, the standarddeviation of all possible observations for the entire population is called the populationstandarddeviation or standarddeviation of the variable x. It...
...Mean and StandardDeviation
The mean, indicated by μ (a lower case Greek mu), is the statistician's jargon for the average value of a signal. It is found just as you would expect: add all of the samples together, and divide by N. It looks like this in mathematical form:
In words, sum the values in the signal, xi, by letting the index, i, run from 0 to N1. Then finish the calculation by dividing the sum by N. This is identical to the equation: μ =(x0 + x1 + x2...
...alternative hypothesis 
D)not enough information 
2.The standard error of difference is .
A)True
B)False
3.In the figure below, if the test value is 1.43, the null hypothesis should not be rejected. 
A)True
B)False
4.When hypothesizing a difference of 0, if the confidence interval does not contain 0, the null hypothesis is rejected.
A)True
B)False
5.For normally distributed populations, if the samples are...
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