To graphically analyze motion, two graphs are commonly used: Displacement vs. Time and Velocity vs. Time. These two graphs provide significant information about motion including distance/displacement, speed/velocity, and acceleration. The displacement and acceleration of a moving body can be obtained from its Velocity vs. Time graph by respectively finding the area and the slope of the graph.

Data Tables – Part I
Displacement (m)Time (s)
0.10 m0.37 s
0.20 m0.586 s
0.30 m0.761 s
0.40 m0.907 s
0.50 m1.041 s
0.60 m1.147 s
0.70 m1.263 s
0.80 m1.351 s
0.90 m1.439 s
1.00 m1.597 s
1.10 m1.646 s
1.20 m1.779 s
1.30 m1.956 s

Part II
Main Photogate at __(m)Time (s)Instantaneous Velocity (m/s) 0.30 m0.098 s0.41 m/s
0.40 m0.072 s0.55 m/s
0.50 m0.06 s0.67 m/s
0.60 m0.053 s0.75 m/s
0.70 m 0.047 s0.85 m/s
0.80 m0.043 s0.93 m/s
0.90 m0.042 s0.95 m/s
1.00 m0.038 s1.05 m/s
1.10 m0.038 s1.05 m/s
1.20 m0.041 s0.98 m/s
1.30 m0.049 s0.82 m/s
1.40 m0.05 s0.8 m/s
1.50 m0.055 s0.72 m/s

Part III

Estimated area
Velocity vs. Time graph
From t=0s to t=0.8s

0.49 m

Slope @ T= 0.8 s
Displacement vs. Time

= 0.6 m/s
Velocity vs. Time

= 0.3 m/s2

(Work shown on graph paper)

Summary Questions

1)Describe the meaning of the slopes of the graphs you obtained in Part III. The slope of the Displacement vs. Time graph (0.6 m/s) represents the velocity of the moving cart at 0.8 seconds. The slope of the Velocity vs. Time graph (0.3 m/s2) represents the acceleration of the moving cart at 0.8 seconds.

2)Describe the motion of the cart based on your result from the Velocity vs. Time graph. Based on the Velocity vs. Time graph, the cart is decelerating because the slope decreases as time passes and the slope represents acceleration/deceleration in a Velocity vs. Time graph.

...Lab II, Problem 3:
Projectile Motion and Velocity
Oct. 06, 2013
Physics 1301W, Professor: Hanany, TA: Vladimir
Abstract
A ball is tossed obliquely. The vectors of position and velocity are measured.
The acceleration is calculated.
Introduction
A toy company is now making an instructional videotape on how to predict the position. Therefore, in order to make the prediction accurate, how the horizontal and vertical components of a ball’s position as it flies through the air should be understood. This experiment is to calculate functions to represent the horizontal and vertical positions of a ball. It does so by measuring and calculating the components of the position and velocity of the ball during the toss. Therefore, we can also calculate the acceleration during the procedure.
Prediction
The x-axis is located on the ground level horizontally, pointing to where the ball is initially thrown, that is opposite the direction the ball flies. The vertical y-axis passes through the highest point of the ball during the fly and point upward.
Since the ball experiences no other force, except for gravity, during the toss. There is no horizontal force. It is predicted that the ball should have a constant horizontal speed, which is the horizontal component of initial velocity. Vertically, it has gravity pulling it down all the time. So it should have an acceleration of –g (minus is for the direction). Since it has a...

...
Centro de investigación y desarrollo de educación bilingüe (CIDEB)
PhysicsLAB REPORT
Uniform Rectilinear Motion
Teacher: Patrick Morris
Alejandra Castillejos Longoria
Group: 205
ID: 1663878
Abstract
The purpose of this experiment, was to prove the concept of the uniform linear motion by using an air track. With this, we demonstrated the impulse and change in momentum, the conservation of energy and the linear motion. We basically learnt to calculate the distance/time, acceleration/time, and velocity/time and graph it. The air track is also used to study collisions, both elastic and inelastic. Since there is very little energy lost through friction it is easy to demonstrate how momentum is conserved before and after a collision. According to the result, the velocity of the object in the air track was constant, it means that it didn’t have acceleration because it has constant velocity.
Introduction
First of all; we should understand what is linear motion. Linear motion is motion along a straight line, and can therefore be described mathematically using only one spatial dimension. Uniform linear motion with constant velocity or zero acceleration. The Air Track can be used to obtain an accurate investigation of the laws of motion. A car or glider travels on a...

...
PhysicsLab Report
How does the length of a string holding a pendulum affect its oscillation?
Method
1. You will need the following apparatus: a pendulum, a piece of string, a clamp, a clamp stand and a timer.
2. Measure out 20cm and attach the metal ball.
3. Establish an angle and let the ball swing for 10 oscillations, timing it and stopping at the 10th one.
4. Write down your results.
5. Repeat steps 2-4 another 2 times so that your results are reliable.
6. Then change the length of the string 4 times, so that you get 5 different sets of results and for each time, repeat it 3 times.
DCP
Raw Data
Data Processing
Calculations:
To find the average of the time, I added all 3 values and then divided by three. For example:
(0.89+0.83+0.89)/3 = 0.87
I calculated the absolute uncertainty by considering the furthest point from the mean. For example:
1.31 (mean) – 1.25 (furthest point from the mean) = 0.06
Therefore my absolute uncertainty is +/- 0.06
I calculated the percentage uncertainty by dividing the absolute uncertainty by the mean and multiplying it by 100, like this:
(0.03/1.70) x100 = 0.18%
Source of uncertainties:
The uncertainties in the measurement came primarily from the equipment. Since we used a ruler that was divided into parts of 0.1cm, the readings were normally rounded up or down. The length of string was constant in all 3 times that we...

...
Free Fall
Rachel Shea
Physics 131 Lab, QL
Hasbrouck 210
Sept. 21, 2014
Abstract
This experiment measures the study of motion by observing the force of gravity acting solely upon an object, and also measures reaction time. If an object is in free fall, the only force acting upon it is gravity. The object used in this experiment was a golf ball that provided some acceleration when dropped. A sensor positioned underneath a table recorded the golf ball’s pattern of motion, when dropped. The main objective of performing this experiment is to measure the velocity and position of the ball to eventually find the acceleration of free fall. A computer program called, DataStudio, was used to create a graph of position vs. time and a graph of velocity vs. time. The second part of the experiment involved randomly dropping a ruler and having your partner catch it to determine reaction time.
Questions
1. The parabolic curves open upward instead of downward because of the golf balls movement over time: where it is dropped from, to where it ends up. The ball begins close to the sensor, then drops to the ground, then bounces back up closer to sensor again, therefore the bounces correspond with the bottom curves of the parabola. If the data were collected from the floor then the curve would open downward. But because the sensor graphs the position from the sensor, the curve was upwards.
2.
-4572009207500
The slope of the...

...trials were performed or if the class data were to be compared and averaged. Performing the experiments under a vacuum and frictionless setting would remove external variables that affect the data leading to more precise numbers. More accurate percent discrepancies illustrating laws of conservation can be achieved by adding more trials and including more sophisticated measuring tools. These techniques would lead to more accurate results to reduce any experimental errors and to better validate the concepts of energy and momentum conservation.
Conclusion
The purpose of the experiment was to investigate simple elastic and inelastic collisions to study the conservation of momentum and energy concepts. The objective of the lab was met since the validity of the Law of Conservation of Momentum was confirmed by determining the relationship of energy and momentum conservation between inelastic and elastic collisions by utilizing percent discrepancy calculations. The calculations state that the percent discrepancies for inelastic collisions were 8.75% and 19.23 % for the equal mass and unequal mass respectively. The percent discrepancies for the equal and unequal mass elastic collisions were 22.07% and 9.78 % respectively. Both of the percent discrepancies for the elastic collisions were close to the 10%-15% range which validates the concept of momentum conservation in inelastic elastic collisions. In regards to conservation of energy,...

... 9/16/14
Physics 01L
Density
Abstract
This experiment was conducted in order to determine the density of the Aluminum metal samples provided in the lab. Specific tools such as the vernier caliper and balance scale were used to measure and record the values found. Given that density is a measurement of mass over volume, both of these quantities would have to be determined experimentally, prior to proceeding with the calculation of the density, for each of the six subjects tested. Being as accurate and precise as possible, the data yielded a density that was similar to that of the accepted value for the density of aluminum. Taking averages of the measurements recorded by both partners may have introduced a variable for error. However, upon calculating the percent error of the results found, it was concluded that there was less than a three percent error, which supported the accuracy and credibility of the experiment.
Data
Table 1: Tabular Presentation
Aluminum
Diameter D1 (cm)
Diameter
D2 (cm)
Average
Diameter (cm)
Height
H1 (cm)
Height
H2 (cm)
Average Height (cm)
Mass (g)
Volume
(cm3)
1
1.27 cm
1.27 cm
1.27 cm
1.55 cm
1.548 cm
1.549 cm
5.6 g
V=1.96cm3
2
1.26 cm
1.266 cm
1.263 cm
2.64 cm
2.64 cm
2.64 cm
9.6 g
V=3.31 cm3
3
1.26 cm
1.266 cm
1.263 cm
4.726 cm
4.728 cm
4.727 cm
16.6 g
V=5.92 cm3
4
1.26 cm
1.268 cm
1.264 cm
6.218 cm
6.216 cm
6.217 cm
21.8 g
V=7.80 cm3
5...

...inertia in motion. To have momentum, the object must be moving. Momentum tells how hard it is to get something to stop or to change directions. Every moving object has momentum and any object with momentum is going to be hard to stop. To stop such an object, it is necessary to apply a force against its motion for a given period of time. The more momentum the object has, the harder it is to be stopped. Thus, it would require a greater amount of force or a longer amount of time or both to bring such an object to a halt. Force acting for a given amount of time will change an object's momentum. As the force acts upon the object for a given amount of time, the object's velocity is changed, and hence, the object's momentum is changed.1 If the force acts opposite the object's motion, it slows the object down. If the force acts in the same direction as the object's motion, then the force speeds the object up. Either way, a force will change the velocity of an object. And if the velocity of the object is changed, then the momentum of the object is changed.
Relating momentum to Newton’s Law of Motion, Newton’s First Law of Motion, which states that an object will remain at rest or keep moving at constant velocity unless it is acted by an external force, keeps the idea that the momentum of an object remains the same unless the object experience an external force, because an object travelling at...